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3 years ago

Given D(5, 7) and E(3, -3), find the midpoint of DE.

Mathematics

1 answer:

just olya [345]3 years ago

4 0

Answer:

$(4,2 )$

Step-by-step explanation:

Midpoint Formula: $(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2} )$

Simply plug in your 2 coordinates into the midpoint formula to find midpoint:

$(\frac{5+3}{2},\frac{7-3}{2} )$

$(\frac{8}{2},\frac{4}{2} )$

$(4,2 )$

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3 years ago

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IRINA_888 [86]

$\dfrac{5}{x^2 - 4} + \dfrac{2}{x} = \dfrac{2}{x - 2}$

$\dfrac{5}{(x + 2)(x - 2)} + \dfrac{2}{x} = \dfrac{2}{x - 2}$

$\dfrac{5}{(x + 2)(x - 2)} \times x(x + 2)(x - 2) + \dfrac{2}{x} \times x(x + 2)(x - 2) = \dfrac{2}{x - 2} \times x(x + 2)(x - 2)$

$5x + 2(x + 2)(x - 2) = 2x(x + 2)$

$5x + 2(x^2 - 4) = 2x^2 + 4x$

$5x + 2x^2 - 8 = 2x^2 + 4x$

$5x - 8 = 4x$

$x - 8 = 0$

$x = 8$

Now we look at the common denominator.

It is x(x + 2)(x - 2).

x cannot be zero, -2 or 2 because that would cause a zero in the denominator.

Since we get x = 8, and x = 8 does not have to be excluded from the domain, the answer is x = 8.

Answer: x = 8

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2 years ago

Given D(5, 7) and E(3, -3), find the midpoint of DE.​

Given D(5, 7) and E(3, -3), find the midpoint of DE.