To answer this we just need to set up a equation:-
895 - 669 - 100 = 126.
SO, after these transactions you will have $126 left.
Hope I helped ya!!
<span>3x + 2y = 8
2y = 8 - 3x
y = (8 - 3x)/2</span>
The expression representing the volume of the prism is given as:
Volume=[base area]*[height]
base area is the area of the pentagon;
The area of pentagon is given by:
Area of pentagon=a^2ntan(180/n)
a=apothem length
n=number of sides
Area=2.8^2*5tan(180/5)
Area=28.48=28.5 cm^2
Therefore the expression for the volume of the prism with height,h, will be:
volume=28.5h cm^3
Range of the data = 13
Solution:
To find the range of the given data:
Let us first define what is range.
Range:
The range of the data set is the difference between the highest value and lowest value of the data set.
i. e. Range = Highest value – Lowest value
In the given number line,
Highest value indicated = 115
Lowest value indicated = 102
Range of the data = 115 – 102
= 13
Range of the data = 13
Hence the range of the given data is 13.
∆BOC is equilateral, since both OC and OB are radii of the circle with length 4 cm. Then the angle subtended by the minor arc BC has measure 60°. (Note that OA is also a radius.) AB is a diameter of the circle, so the arc AB subtends an angle measuring 180°. This means the minor arc AC measures 120°.
Since ∆BOC is equilateral, its area is √3/4 (4 cm)² = 4√3 cm². The area of the sector containing ∆BOC is 60/360 = 1/6 the total area of the circle, or π/6 (4 cm)² = 8π/3 cm². Then the area of the shaded segment adjacent to ∆BOC is (8π/3 - 4√3) cm².
∆AOC is isosceles, with vertex angle measuring 120°, so the other two angles measure (180° - 120°)/2 = 30°. Using trigonometry, we find
where 
is the length of the altitude originating from vertex O, and so
where 
is the length of the base AC. Hence the area of ∆AOC is 1/2 (2 cm) (4√3 cm) = 4√3 cm². The area of the sector containing ∆AOC is 120/360 = 1/3 of the total area of the circle, or π/3 (4 cm)² = 16π/3 cm². Then the area of the other shaded segment is (16π/3 - 4√3) cm².
So, the total area of the shaded region is
(8π/3 - 4√3) + (16π/3 - 4√3) = (8π - 8√3) cm²
