Ask question

Ask question

All categories

3 years ago

14

During World War II, mass spectrometers were used to separate the radioactive uranium isotope U-235 from its far more common iso

tope, U-238. Estimate the radius of the circle traced out by a singly ionized lead atom moving at the same speed.

1 answer:

mariarad [96]3 years ago

6 0

Answer:

21.55 m

Explanation:

You might be interested in

In 0.60 seconds, a projectile goes from 0 to 610 m/s. What is the acceleration of the projectile?

IceJOKER [234]

Answer: $a=1016.66 m/s^{2}$

Explanation:

Acceleration $a$ is expressed in the following formula:

$a=\frac{V_{f}-V_{o}}{t}$

Where:

$V_{f}=610 m/s$ is the final velocity of the projectile

$V_{o}=0 m/s$ is the initial velocity of the projectile

$t=0.6 s$ is the time

Solving:

$a=\frac{610 m/s-0 m/s}{0.6 s}$

$a=1016.66 m/s^{2}$ This is the acceleration of the projectile

6 0

4 years ago

50 POINTS AND BRAINLEIST A Ferris wheel has a mechanical advantage of ___________________________ one and the trade off is that

kiruha [24]

Answer:

C.) The same as one

Explanation:

Because the Ferris wheel has two bars at the side that keep it in place so it doesn't roll away. The Ferris wheel only moves in one place. If the ferris wheel did roll then you would have a greater than one. If it did roll it would be dangerous.

5 0

3 years ago

Read 2 more answers

What is the common trait of all main-sequence stars?.

Andrei [34K]

Answer:

They generate energy through hydrogen fusion in their core.

Explanation:

hope this helps :)

5 0

2 years ago

Is the change in velocity divided by the time needed for the change to occur.

Montano1993 [528]

Answer: yes

Explanation:

6 0

3 years ago

As an intern at an engineering firm, you are asked to measure the moment of inertia of a large wheel for rotation about an axis

klio [65]

Hi there!

We can begin by finding the acceleration of the block.

Use the kinematic equation:

$d = v_0t + \frac{1}{2}at^2$

The block starts from rest, so:

$d = \frac{1}{2}at^2\\\\12 = \frac{1}{2}a(4^2)\\\\\frac{24}{16} = a = 1.5 m/s^2$

Now, we can do a summation of forces of the block using Newton's Second Law:

$F = ma = m_bg - T$

mb = mass of the block

T = tension of string

Solve for tension:

$T = m_bg - ma = 8.2(9.8) - 8.2(1.5) = 68.06 N$

Now, we can do a summation of torques for the wheel:

$\Sigma \tau = rF\\\\\Sigma\tau = rT$

Rewrite:

$I\alpha = rT$

We solved that the linear acceleration is 1.5 m/s², so we can solve for the angular acceleration using the following:

$\alpha = a/r\\\\\alpha = 1.5/.42= 3.57 rad/sec^2$

Now, plug in the values into the equation:

$I(3.57) = (0.42)(68.06)\\\\I = (0.42)(68.06)/(3.57) = \boxed{8.00 kgm^2}$

8 0

3 years ago