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dusya [7]
2 years ago
14

A. Besides protons, what other particles make up an atom? Write 2 - 3 sentences identifying the attractive force acts between a

proton and each of these other particles.
b. Identify the element whose atoms have 11 protons. It is a metal, nonmetal, or metalloid? Write 1 - 2 sentences describing how an atom of this element changes when it forms an ionic bond.
Physics
1 answer:
Vinil7 [7]2 years ago
6 0

Electric force is present between proton and electron of an atom.

<h3>What is the attractive force present between a proton and electron?</h3>

The attractive force between the electrons and the proton of the nucleus is called the electric force. This force attract electron towards the nucleus so that it can't escape from the atom easily so this force is very important for the atom.

<h3>How an atom of this element changes when it forms an ionic bond?</h3>

An atom of this element changes when it forms an ionic bond because the number of electron decreases due to losing of electron in order to get stability. We know that ionic bond forms between atoms when electron is lost or gain by the atom.

So we can conclude that electric force is present between proton and electron of an atom.

Learn more about force here: brainly.com/question/12970081

#SPJ1

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The magnetic field in a cyclotron is 1.25 T, and the maximum orbital radius of the circulating protons is 0.40 m. (a) What is th
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1.92 x 10⁻¹²J

Explanation:

The magnetic force from the magnetic field gives the circulating protons gives the particle the necessary centripetal acceleration to keep it orbiting round the circular path. And from Newton's second law of motion, the force(F) is equal to the product of the mass(m) of the proton and the centripetal acceleration(a). i.e

F = ma

Where;

a = \frac{v^2}{r}             [v = linear velocity, r = radius of circular path]

=> F = m\frac{v^2}{r}           ------------(i)

We also know that the magnitude of this magnetic force experienced by the moving charge (proton) in a magnetic field is given by;

F = q v B sin θ       ----------(ii)

Where;

q = charge of the particle

v = velocity of the particle

B = magnetic field

θ = the angle between the velocity and the magnetic field.

Combining equations (i) and (ii) gives

m\frac{v^2}{r} = q v B sin θ           [θ = 90° since the proton is orbiting at the maximum orbital radius]

=> m\frac{v^2}{r} = q v B sin 90°

=> m\frac{v^2}{r} = q v B

Divide both side by v;

=> m\frac{v}{r} = qB

Make v subject of the formula

v = \frac{qBr}{m}

From the question;

B = 1.25T

m = mass of proton = 1.67 x 10⁻²⁷kg

r = 0.40m

q = charge of a proton = 1.6 x 10⁻¹⁹C

Substitute these values into equation(iii) as follows;

v = \frac{(1.6*10^{-19})(1.25)(0.4)}{(1.67*10^{-27})}

v = 4.79 x 10⁷m/s

Now, the kinetic energy, K, is given by;

K = \frac{1}{2}mv²

m = mass of proton

v = velocity of the proton as calculated above

K = \frac{1}{2}(1.67*10^{-27} * (4.79 * 10^7)^2 )

K = 1.92 x 10⁻¹²J

The kinetic energy is 1.92 x 10⁻¹²J

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