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dusya [7]
1 year ago
14

A. Besides protons, what other particles make up an atom? Write 2 - 3 sentences identifying the attractive force acts between a

proton and each of these other particles.
b. Identify the element whose atoms have 11 protons. It is a metal, nonmetal, or metalloid? Write 1 - 2 sentences describing how an atom of this element changes when it forms an ionic bond.
Physics
1 answer:
Vinil7 [7]1 year ago
6 0

Electric force is present between proton and electron of an atom.

<h3>What is the attractive force present between a proton and electron?</h3>

The attractive force between the electrons and the proton of the nucleus is called the electric force. This force attract electron towards the nucleus so that it can't escape from the atom easily so this force is very important for the atom.

<h3>How an atom of this element changes when it forms an ionic bond?</h3>

An atom of this element changes when it forms an ionic bond because the number of electron decreases due to losing of electron in order to get stability. We know that ionic bond forms between atoms when electron is lost or gain by the atom.

So we can conclude that electric force is present between proton and electron of an atom.

Learn more about force here: brainly.com/question/12970081

#SPJ1

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Answer:

vp = 0.94 m/s

Explanation

Formula

Vp = position/ time

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Answer:

total distance = 1868.478 m

Explanation:

given data

accelerate = 1.68 m/s²

time = 14.2 s

constant time = 68 s

speed = 3.70 m/s²

to find out

total distance

solution

we know train start at rest so final velocity will be after 14 .2 s is

velocity final = acceleration × time      ..............1

final velocity = 1.68 × 14.2

final velocity = 23.856 m/s²

and for stop train we need time that is

final velocity = u + at

23.856 = 0 + 3.70(t)

t = 6.44 s

and

distance = ut + 1/2 × at²     ...........2

here u is initial velocity and t is time for 14.2 sec

distance 1 = 0 + 1/2 × 1.68 (14.2)²

distance 1 = 169.37 m

and

distance for 68 sec

distance 2= final velocity × time

distance 2= 23.856 × 68

distance 2 = 1622.208 m

and

distance for 6.44 sec

distance 3 = ut + 1/2 × at²

distance 3 = 23.856(6.44) - 0.5 (3.70) (6.44)²

distance 3 = 76.90 m

so

total distance = distance 1 + distance 2 + distance 3

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total distance = 1868.478 m

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