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dusya [7]
2 years ago
14

A. Besides protons, what other particles make up an atom? Write 2 - 3 sentences identifying the attractive force acts between a

proton and each of these other particles.
b. Identify the element whose atoms have 11 protons. It is a metal, nonmetal, or metalloid? Write 1 - 2 sentences describing how an atom of this element changes when it forms an ionic bond.
Physics
1 answer:
Vinil7 [7]2 years ago
6 0

Electric force is present between proton and electron of an atom.

<h3>What is the attractive force present between a proton and electron?</h3>

The attractive force between the electrons and the proton of the nucleus is called the electric force. This force attract electron towards the nucleus so that it can't escape from the atom easily so this force is very important for the atom.

<h3>How an atom of this element changes when it forms an ionic bond?</h3>

An atom of this element changes when it forms an ionic bond because the number of electron decreases due to losing of electron in order to get stability. We know that ionic bond forms between atoms when electron is lost or gain by the atom.

So we can conclude that electric force is present between proton and electron of an atom.

Learn more about force here: brainly.com/question/12970081

#SPJ1

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Waves with higher amplitude transfer ____energy.
natali 33 [55]

Answer:

- Waves with higher amplitude transfer HIGHER energy.

- Waves with higher frequency transfer HIGHER energy.

3 0
3 years ago
Why do lithospheric plates move constantly?
Charra [1.4K]
I think the correct answer from the choices listed above is option C. Lithospheric plates move constantly due to the density differences. Lithospheric plates<span> are another name for tectonic plates, which are part of the Earth's uppermost layer, the crust.</span>
6 0
3 years ago
How many strings of length 10 over the alphabet (a, b, c, d] have at least one b somewhere in the string?
Lapatulllka [165]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The correct option is  B

Explanation:

   The number  of alphabet is  n= 4  (a , b , c , d )

Generally the total  number of  string of length 10 over the 4 alphabets is  

     N  =  4^{10}

Gnerally the number of string of length 10 that does not include b is  

     T =  3^{10}    

Generally the number of strings of length 10 over the 4  alphabets that have at least one alphabet b  somewhere in the string is  

        G  =  N - T

=>    G  =  4^{10} -  3^{10}

8 0
3 years ago
Two train whistles, and , each have a frequency of 392 Hz. is stationary and is moving toward the right (away from ) at a speed
trasher [3.6K]

Answer:

Part a)

f = 371.1 Hz

Part b)

f = 417.7 Hz

Part c)

beat frequency = 46.6 Hz

Explanation:

Part a)

Due to doppler's Effect the frequency of the sound heard by the train which is moving away from the observer is given as

f_1 = f_0\frac{v + v_o}{v + v_s}

f_1 = 392(\frac{340 + 15}{340 + 35})

f_1 = 371.1 Hz

Part b)

Now from the second train which is approaching the person we can say

f_2 = f_0\frac{v - v_o}{v - v_s}

f_2 = 392(\frac{340 - 15}{340 - 35})

f_2 = 417.7 Hz

Part c)

As we know that beat frequency is the difference in the frequency from two sources

f_b = f_2 - f_1

f_b = 417.7 - 371.1 = 46.6 Hz

8 0
3 years ago
The age of the universe in seconds
Marianna [84]

Answer:

4.351968e+17 seconds

Explanation:

So I googled age of the universe and it says 13.8 billion years.

you'll have to do some conversions:

in one year, there are 365 days. in one day, there are 24 hours. in one hour, there are 3600 seconds.

\frac{1 year}{365 days} x \frac{1 day}{24 hours} x \frac{1 hour}{3600 seconds}

so you have to add in the current age of the universe to that equation:

\frac{x seconds}{13.8 bil years} x \frac{1 year}{365 days} x \frac{1 day}{24 hours} x \frac{1 hour}{3600 seconds}

arranged so that the proper "units" will read as "x seconds" at the end of the equation.

then you do the math to find x:

13.8 billion x 365 x 24 x 3600 = 4.351968e+17 seconds.

which would be 435,196,800,000,000,000 seconds

Hope this helps :)

7 0
4 years ago
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