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sergiy2304 [10]
2 years ago
10

Is the change in velocity divided by the time needed for the change to occur.

Physics
1 answer:
Montano1993 [528]2 years ago
6 0

Answer: yes

Explanation:

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An ice cream truck is going 25m/s to the East. It accelerates to 45m/s in the same direction over 5s. What is its acceleration?
Naya [18.7K]

Hello!

We can use the kinematic equation:
a = \frac{v_f - v_i}{t}

a = acceleration (m/s²)

vf = final velocity (45 m/s)
vi = initial velocity (25 m/s)

t = time (5 sec)

Plug in the givens:
a = \frac{45-25}{5} = \frac{20}{5} = \boxed{4 m/s^2}

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3 years ago
A soap bubble usually pops because some part of it becomes too thin due to evaporation or drainage of fluid. The change in thick
Lapatulllka [165]

Answer:

To understand why the change in thickness also changes the color of light the bubble reflects, we definitely know that

mλ = dsinθ

when d sin θ = mλ, we expect constructive interference

d = distance between the slits

θ = the angle relative to the incident direction

m = order of the interference

Hence, a change in the thickness will also cause a change in the wavelength, and as wavelength changes, various colors are generated.

The light's path difference is therefore generated as a result of the thickness variation of the soap bubble.

Explanation:

To understand why the change in thickness also changes the color of light the bubble reflects, we definitely know that

mλ = dsinθ

when d sin θ = mλ, we expect constructive interference

d = distance between the slits

θ = the angle relative to the incident direction

m = order of the interference

Hence, a change in the thickness will also cause a change in the wavelength, and as wavelength changes, various colors are generated.

The light's path difference is therefore generated as a result of the thickness variation of the soap bubble.

5 0
3 years ago
Professional Application: A 30,000-kg freight car is coasting at 0.850 m/s with negligible friction under a hopper that dumps 11
Nataliya [291]

Answer:

0.182 m/s

Explanation:

m1 = 30,000 kg, m2 = 110,000 kg, u1 = 0.85 m/s

let the velocity of loaded freight car is v

Use the conservation of momentum

m1 x u1 + m2 x 0 = (m1 + m2) x v

30,000 x 0.85 = (30,000 + 110,000) x v

v = 0.182 m/s

5 0
3 years ago
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