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3 years ago

-18 ≥ 4 + 2q Solve for me, please.

Mathematics

1 answer:

Firlakuza [10]3 years ago

5 0

Answer

q≤ -11

thats your answer i believe, just typing this because it said it was too short to post

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Scott burned 20 calories per minute jogging for x minutes and 5 calories per minute for biking for y minutes. He spent a total o

stiv31 [10]

Answer:

x = 112

Step-by-step explanation:

We can create two equations 1. one that calculates calories burned and 2.another that calculates minutes:

20*x + 5*y = 1200

x + y = 120

Then we can solve for x

x = 120 - y

then we can plug that into the top equation:

20(120 - y) + 5y = 1200

divide by 5:

4(120 - y) + y = 240

distribute:

480 - 4y + y = 240

and then do all that combining like factors what not and simplify and solve:

480 - 3y = 240

-3y = -240

y = 8

NOW WE CAN JUST PLUG IN THE ANSWER FOR Y TO FIND X

8+x =120

x = 112

7 0

3 years ago

Justin is asked to solve the following system of linear equations using the elimination method.

vekshin1

Answer:

B, 5

Step-by-step explanation:

Got it correct

3 0

3 years ago

Suppose that we have the following sequence :

Jlenok [28]

$a_n=\dfrac12a_{n-1}$
$a_n=\dfrac1{2^2}a_{n-2}$
$a_n=\dfrac1{2^3}a_{n-3}$
$a_n=\cdots=\dfrac1{2^{n-1}}a_1$
$a_n=\dfrac1{2^{n-1}}$

$b_n=b_{n-1}+\dfrac1{2^{n-1}}$
$b_n=b_{n-2}+\dfrac1{2^{n-1}}+\dfrac1{2^{n-2}}$
$b_n=b_{n-3}+\dfrac1{2^{n-1}}+\dfrac1{2^{n-2}}+\dfrac1{2^{n-3}}$
$b_n=\cdots=b_1+\dfrac1{2^{n-1}}+\dfrac1{2^{n-2}}+\cdots+\dfrac12$
$b_n=a_1+\displaystyle\sum_{k=1}^{n-1}\frac1{2^{n-k}}$
$b_n=1+\displaystyle\sum_{k=1}^{n-1}\frac1{2^{n-k}}$
$b_n=\displaystyle\sum_{k=1}^n\frac1{2^{n-k}}$
$b_n=\displaystyle\frac1{2^n}\underbrace{\sum_{k=1}^n2^k}_{S_n}$

$S_n=1+2+2^2+\cdots+2^{n-1}+2^n$
$\implies2S_n=2+2^2+2^3+\cdots+2^n+2^{n+1}$
$\implies S_n-2S_n=-S_n=1-2^{n+1}$
$\implies S_n=2^{n+1}-1$

$b_n=\dfrac{2^{n+1}-1}{2^n}=2-\dfrac1{2^n}$

$\implies b_{50}=2-\dfrac1{2^{50}}\approx1.99999999999999911182158$

$\implies b_{10^6}=2-\dfrac1{2^{10^6}}\approx2.00000000000000000000000$

8 0

3 years ago

Find the slope for this relatioonship

yulyashka [42]

Ann’s and uieieiw772828

7 0

3 years ago

Please ASAP please

Mars2501 [29]

Answer:

A)3.125hr

B)53.325mi

Step-by-step explanation:

speed=distance/time

an hour and 15min=1.25hr

32/1.25=25.6mi/hr

80/25.6=3.125hr

2hr and 5min=2+5/60=2.083hr

2.083x25.6=53.325mile

7 0

3 years ago