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AleksAgata [21]
3 years ago
12

What is the mode of the following numbers? 4,9,6, 3, 4,2

Mathematics
1 answer:
Alexxx [7]3 years ago
3 0

Answer:

4

Step-by-step explanation:

Whichever number appears the most in the list of numbers which in this is 4

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In her sixth-grade social studies class, Mrs. Davis has 22 students, 12 of whom are girls. If one
tatiyna

Answer:

5/11

Step-by-step explanation:

Please let me know if you want me to add an explanation as to why this is the answer. I can definitely do that, I just wouldn’t want to write it if you don’t want me to :)

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Use the drop-down menus to complete the statements about Euler's life after he lost his sight. After the cataract took Euler's s
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About 450 books and articles Euler completed after he lost his sight entirely.

<h3>Who was Leonhard Euler?</h3>

Leonhard Euler was a mathematician from Switzerland. He introduced the fundamentals of graph theory and topology.

His main field of work includes number theory, mechanics, fluid mechanics, and many more.

The life span of Euler was between 1707 and 1783. In the last few years of his life, he lost the eye sight. But the eye sight loss doesn't affect him from doing his work. In his lifespan, he published around 886 books and articles on various fields or science, mathematics and engineering.

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8 0
2 years ago
Need help Soon as possible
netineya [11]

Answer:

D; D

Step-by-step explanation:

The common difference of the first sequence is 10, so the coefficient is 10. The first term minus the common difference is -8, so that is the constant

The common difference of the second sequence is 3, so the coefficient is 3. The first term minus the common difference is -9, so that is the constant.

7 0
3 years ago
Solve for x.<br> 3(3x - 1) + 23 - x) = 0
enot [183]
9x-3+69-3x=0
6x+66=0
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3 0
3 years ago
If the product of two positive fractions a and b is 15/56, find three pairs of possible values for a and b
Andrews [41]

Answer:

First possible pairs = (3/7)*(5/8) = 15/56

second possible pairs = (3/4)*(5/14) = 15/56

third possible pairs = (1/2)*(15/28) = 15/56

Step-by-step explanation:

According to the question,

a x b = 15/56

three possible pairs will be as follows:

Before proceeding to make possible pairs, we have to know the prime factorization of the numbers -

15 = 1, 3, 5, 15

56 = 1, 2, 4, 7, 8, 14, 28, 56

As we need three possible pairs, we have to check which pairs take us to 15/56. Again, since the fraction is positive, therefore, the fractions will be proper. Therefore, 3/2, or 5/4 will not be counted. Therefore,

First possible pairs = (3/7)*(5/8) = 15/56

second possible pairs = (3/4)*(5/14) = 15/56

third possible pairs = (1/2)*(15/28) = 15/56

fourth possible pairs = (3/8)*(5/7) = 15/56

So, we can get those four possible pairs. Among those, first 3 pairs are different. Therefore, those are possible pairs.

4 0
3 years ago
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