The Price of Car A rounded to the Nearest £100 is £12400
The Price of Car B rounded to the Nearest £100 is £16800
The Price of Car C rounded to the Nearest £100 is £14600
Difference between the Rounded Price and Original Price of Car A :
⇒ (£12400 - £12380) = £20
Difference between the Rounded Price and Original Price of Car B :
⇒ (£16800 - £16760) = £40
Difference between the Rounded Price and Original Price of Car C :
⇒ (£14600 - £14580) = £20
From the above, We can Notice that :
The Price of Car B changes by the greatest amount.
Answer:
The answer is the sum of three times a number and six, divided by the difference of seven times the number and nine
Step-by-step explanation:
3p = three x a number
7p = seven x a number
3p+6 = sum of three x a number plus six
7p-9 = difference of seven x the number minus nine
(3p+6)/(7p-9) = sum of three times x number plus six, divided by the difference of seven x the number - nine
Answer:
ab= 7.8
ac= 6
bc=5
Step-by-step explanation:
3^2 + 16
= (3 • 3) + 16
= 9 + 16
= 25
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