9514 1404 393
Answer:
   R80: 12
   G150: 54
   Best Profit: $582
Step-by-step explanation:
Let x and y represent the numbers of R80 and G150 players, respectively. The constraints of the problem are ...
   0 ≤ x ≤ 18 . . . . . a maximum of 18 R80 can be built
   0 ≤ y . . . . . . . . . only non-negative numbers can be built
   9x +3y ≤ 270 . . . . ounces of plastic used cannot exceed 270
   2x +6y ≤ 348 . . . . ounces of metal used cannot exceed 348
The objective is to maximize the profit function ...
   P(x, y) = 8x +9y
The attached graph shows profit is a maximum of $582 per week when 12 R80 players and 54 G150 players are produced.
_____
Since the maximum profit is at a value of x less than 18, we didn't bother to graph that constraint.
 
        
             
        
        
        
Ok? what's the rest, u can't solve unless there's a question like : how many hours does he have to work in order to go on vacation, I'm sorry but u make no sense
        
             
        
        
        
Can you show a better photo some of the question is cut off
        
                    
             
        
        
            
            
                Find the median of: 1, 3, 4, 6, 2, 4, 5, 6, 2, 3, 1, 4, 0, 4, 4, 4, 8, 9, 7, 4 
                Alborosie             
         
        
Solution,
Arranging the data in ascending order:
0,1,1,2,2,3,3,4,4,4,4,4,4,4,5,6,6,7,8,9
N(total number of items)= 20
Now,
Median:

Again,
Median:

 
        
                    
             
        
        
        
Answer:
C. c = 64 + 2w
Step-by-step explanation:
You're starting with 64 customers and you're gaining 2 for each week.
<em>good luck, i hope this helps :)</em>