Your answer would be A because $4800 is your starting number and it increases 2% every year. How much is it in 20 years?
You use the formula ab^x
a is your starting number
b is the percentage
x is always the length of time
Since you are increasing and trying to get its worth larger than what it was before you use a number larger than one hundred percent in this case the number would be 1.02.
Y=4800(1.02)^20
Y=$7132.55
Answer:
16
Step-by-step explanation:
Answer:
Step-by-step explanation: (Equation 2) = 12(-12+9y/4) - 10y = -8
-144+108y/4 - 10y = -8
-144 + 108y - 40y/4 = -8
-144 + 108y - 40y = -32
108y - 40y = -32+144
68y = 112
Y= 1.64
2-4x+9y=14
12x-10y= -8
2-14+9y = 4x
-12 + 9y = 4x ( equation 3)
(Put in equation 2)
Answer: C
<u>Step-by-step explanation:</u>
∑ 8(
)⁽ⁿ⁻¹⁾ from n = 1 to n = 5
n = 1 → 8()⁽¹⁻¹⁾
= 8 = 
n = 2 → 8()⁽²⁻¹⁾
= 
= 
n = 3 → 8()⁽³⁻¹⁾
= 
= 
n = 4 → 8()⁽⁴⁻¹⁾
= 
= 
n = 5 → 8()⁽⁵⁻¹⁾
= 
=
Sum = 
= 408.99
13.5 = 30% of 45
4.5 = 15% of 30
4.6 = 23% of 20
4.2 = 60% of 7
Hope this helps!!
