Answer:
kinetic friction may be greater than 400 N or smaller than 400 N
Explanation:
As we know that maximum value of static friction on the rough surface is known as limiting friction and the formula of this limiting friction is known as

now when object is sliding on the rough surface then the friction force on that surface is known as kinetic friction and the formula of kinetic friction is known as

now we know that

so here value of limiting static friction force is always more than kinetic friction
also we know that
initially when body is at rest then static friction value will lie from 0 N to maximum limiting friction
and hence kinetic friction may be greater than static friction or if the static friction is maximum limiting friction then kinetic friction is smaller than static friction
so kinetic friction may be greater than 400 N or smaller than 400 N
Answer:
a. 
b. 21.64 m/s
Explanation:
Let g = 9.81m/s2
a. The weight of the block is product of its mass and gravitational acceleration

which is also the normal force acting on the block from the floor so it stays balanced.
N = 71.225N
The static friction of the block is product of its normal force from the floor and the friction coefficient

For the block to move, the force generated by the impact must be at least equal to the static friction.

The impulse is product of this force and time duration of impact.

As impulse is generated by change in momentum of the ball, which is product of its mass and velocity v



b. 
If the results of the experiment differ; so u repeat the experiment to notice a pattern.
Answer:
1512N
Explanation:

here, m=63kg
a=24ms^-²
so, f=ma=63×24=1512N (Newton)
Initially jet is moving horizontally
so we know that


now we have
PART a)
Net horizontal force is given as



Part b)
since the acceleration in vertical direction is zero
so as per Newton's law we know


PART c)
speed of the jet increases in vertical direction from ZERO to 21 m/s in 20 seconds and speed increases in horizontal direction from 95 m/s from 80 m/s in same time
vertical acceleration

horizontal acceleration

now net horizontal force will be


PART d)
Now for vertical force we have


PART e)
Now after reaching the cruising level the horizontal speed becomes constant and in vertical direction speed decrease to ZERO from 21 m/s in 13 s
So we have


now we have horizontal force as

Part f)

