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BigorU [14]
3 years ago
13

A roller coaster has a vertical loop with radius 15.8 m. with what minimum speed should the roller coaster car be moving at the

top of the loop so that the passengers do not lose contact with the seats?
Physics
1 answer:
statuscvo [17]3 years ago
5 0
The centripetal force will balance the gravitional: 
<span> m*g=m*v^2/R 
</span><span> v=sqrt(g*R) 
</span><span> Plug in the numbers 
</span><span> v=sqrt(9.81*15.8) 
</span> v=<span> <span>12.45</span></span><span> m/s </span>
 
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Neutron can be absent 
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Which electromagnetic wave has the lowest frequencies (less than 3×109 hertz)?
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Answer:

Radio waves

Explanation:

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Radio waves are the electromagnetic waves with lowest frequency, their frequency is lower than 300 GHz (3\cdot 10^{11} Hz) and therefore they are the electromagnetic waves with lowest energy (in fact, the energy of an electromagnetic wave is proportional to its frequency). They are generally used for radio and telecommunications since this type of waves can travel up to long distances.

5 0
4 years ago
Read 2 more answers
A voltage V is applied to the primary coil of a step-up transformer with a 3:1 ratio of turns between its primary and secondary
Snezhnost [94]

Explanation:

Let N_p\ and\ N_s are the number of turns in primary and secondary coil of the transformer such that,

\dfrac{N_p}{N_s}=\dfrac{1}{3}

A resistor R connected to the secondary dissipates a power P_s=100\ W

For a transformer, \dfrac{N_s}{N_p}=\dfrac{V_s}{V_p}

V_s=(\dfrac{N_s}{N_p})V_p

V_s=3V_p...............(1)

The power dissipated through the secondary coil is :

P_s=\dfrac{V_s^2}{R}

100\ W=\dfrac{V_s^2}{R}

V_p^2=\dfrac{100R}{9}.............(2)

Let N_p'\ and\ N_s' are the new number of turns in primary and secondary coil of the transformer such that,

\dfrac{N_p'}{N_s'}=\dfrac{1}{24}

New voltage is :

V_s'=(\dfrac{N_s'}{N_p'})V_p'

V_s'=24V_p...............(3)

So, new power dissipated is P_s'

P_s'=\dfrac{V_s'^2}{R}

P_s'=\dfrac{(24V_p)^2}{R}

P_s'=24^2\times \dfrac{(V_p)^2}{R}

P_s'=24^2\times \dfrac{(\dfrac{100R}{9})}{R}

P_s'=6400\ Watts

So, the new power dissipated by the same resistor is 6400 watts. Hence, this is the required solution.

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6 0
3 years ago
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