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3 years ago

4. Which statement best describes the movement of particles when a wave travels through a medium? The particles are (10 points)

Physics

2 answers:

Bingel [31]3 years ago

7 0

The answer is D . temporarily displaced and return to their normal position whenthe wave passes.

GalinKa [24]3 years ago

5 0

Answer:

D.temporarily displaced and return to their normal position when the wave passes.

Explanation:

When a wave propagates in a medium, it does going through the particles that exist in that space.

Those are altered by the wave that crosses them but, that phenomenon only lasts the time takes to pass through, then the particles return to their natural state.

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Robert dropped his new iPhone from his balcony. It hit the ground 3.5 seconds later. What was the height of his balcony?

Lorico [155]

its B. 60 meters

Explanation:

cause I looked up a calculator and solved it

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3 years ago

What is Humpty Dumpty's momentum if he has a mass of 56kg and is walking to the wall at a rate of 3 m/s?

Sophie [7]

Answer:

168

Explanation:

56 x 3

have a nice day

5 0

3 years ago

Currents during lightning strikes can be up to 50000 A (or more!). We can model such a strike as a 49500 A vertical current perp

Tema [17]

Answer:

59.4 N

Explanation:

The force exerted on a current-carrying wire due to a magnetic field perpendicular to the wire is given by

$F=ILB$

where

I is the current in the wire

L is the length of the wire

B is the strength of the magnetic field

Here in this problem, we model the strike as a current-carrying wire, so we have:

I = 49,500 A is the current

L = 1 m is the length (we want to find the force per each meter of length)

$B=12 G = 12\cdot 10^{-4} T$ is the strength of the magnetic field

Therefore, the force on each meter of the current due to the magnetic field is:

$F=(49,500)(1)(12\cdot 10^{-4})=59.4 N$

3 0

3 years ago

A boy whirls a ball on a string 1.0 m long in a horizontal circle at 50 rpm. If the mass of the ball is 0.22 kg

vazorg [7]

Hi there! :)

We can begin by doing a summation of forces on the ball. In the horizontal direction, we have the force of tension:
$F_{Net} = T$

The tension force results in a centripetal force experienced by the ball. The equation of centripetal force is equivalent to:
$F_C = m\omega^2 r$

$F_C$ = Centripetal force (N)
m = mass of ball (0.22 kg)

ω = angular speed of ball(? rad/sec, must convert rpm to rad/sec)

r = radius/length of string (1.0 m)

We must begin by converting rpm to rad/sec:

$\frac{50 rev}{min} * \frac{2\pi rad}{1 rev}* \frac{1 min}{60 sec} = 5.236 \frac{rad}{s}$

Now, we can set tension equal to the centripetal force and solve. $T = F_{Net} = F_C\\\\T = m\omega^2 r\\\\T = (0.22)(5.236^2)(1) = \boxed{6.031 N}$

6 0

2 years ago

How much work was done by a hot air balloon to lift up a 100 Newton to a height of 300 meters?

Monica [59]

So, the work was done by that hot air-balloon is <u>30,000 J or 30 kJ</u>.

<h3>Introduction</h3>

Hi ! In this question, I will help you. <u>Work is the amount of force exerted to cause an object to move a certain distance from its starting point</u>. In physics, the amount of work will be proportional to the increase in force and increase in displacement. Amount of work can be calculated by this equation :

$\boxed{\sf{\bold{W = F \times s}}}$