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rewona [7]
2 years ago
9

Daughter’s current age is 6 years which is 1/5 th of her mother’s age. After how many years mother’s age will be three times gre

ater than daughter’s age.
Mathematics
1 answer:
kifflom [539]2 years ago
5 0

Answer:

6 years

Step-by-step explanation:

6 = ⅕m

m = 30

"mother's age will be three times greater than daughter's age"—Not sure what "three times greater than" means. I will interpret it as: "mother's age will be three times daughter's age."

In x years, mother will be 30+x and the daughter will be 6+x.

30+x = 3(6+x) = 18+3x

12 = 2x

x = 6

In 6 years, the mother will be 36 and the daughter will be 12.

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The rigorous way to do this would be to compute a few integrals, but less work is usually better. Each of these probabilities correspond to the areas of rectangles. Each rectangle will have a height of 1, and the probability of interest will tell you everything you need to know about their lengths.

\mathbb P(0\le X\le0.4)\implies \text{length}=0.4\implies\mathbb P(0\le X\le0.4)=0.4\times1=0.4

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Alternatively, you can use the fact that \mathbb P(0.4\le X\le 1)=1-\mathbb P(0\le X\le 0.4) to get the same result.

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\mathbb P(X\le0.6)\implies \text{length}=0.6\implies\mathbb P(X\le0.6)=0.6

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3 0
3 years ago
Ramon caught twice as many fish as his brother. If his brother caught F amount of fish, write an expression that shows how many
arlik [135]
2•F is the way to write the expression.
6 0
3 years ago
What is the product of z1 and z2 if
MaRussiya [10]

Answer:

308[cos(45) + isin(45)]

Step-by-step explanation:

z1×z2:

Modulus: r1 × r2

= 7×44 = 308

Argument: theta1 + theta2

= -70 + 115 = 45

z1z2 = 308[cos(45) + isin(45)]

Or

z1z2 = 154sqrt(2) + (i)154sqrt(2)

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8 0
3 years ago
Find the midpoint of if A(-3, 8) andB(-7, -6).
Mama L [17]

Answer:

(-5,1)

Step-by-step explanation:

8 0
2 years ago
What is the equation of a circle with center (−8, 3) and radius 8?
Genrish500 [490]

Answer:

x^2 + y^2 + 16x + 6y + 9 = 0

Step-by-step explanation:

Using the formula for equation of a circle

(x - a)^2 + (y + b)^2 = r^2

(a, b) - the center

r - radius of the circle

Inserting the values given in the question

(-8,3) and r = 8

a - -8

b - 3

r - 8

[ x -(-8)]^2 + (y+3)^2 = 8^2

(x + 8)^2 + (y + 3)^2 = 8^2

Solving the brackets

( x + 8)(x + 8) + (y +3)(y+3) = 64

x^2 + 16x + 64 + y^2 + 6y + 9 = 64

Rearranging algebrally,.

x^2 + y^2 + 16x + 6y + 9+64 - 64 = 0

Bringing in 64, thereby changing the + sign to -

Therefore, the equation of the circle =

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7 0
3 years ago
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