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Nesterboy [21]
2 years ago
11

Solve the inequality below. Use the drop down menus' to describe the solution and its graph.

Mathematics
1 answer:
defon2 years ago
3 0

Answer:

x>-4

Step-by-step explanation:

Easy, -7x + 13 > 41 from here you subtract 13 from each side giving you -7x >28 after this you divide by -7.

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which two points should the line of best fit go through to best represent the data in the scatter plot (1,16) and (2,15) (1,16)
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You simply have to plot the point and draw a line that passes through most of them
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You start at (5, -1). You move up 5 units. Where do you end? On a coordinate plane
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0,-1

Step-by-step explanation:

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2 years ago
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23/7y state restrictions
qwelly [4]

The restrictions on the variable of the given rational fraction is y ≠ 0.

<h3>The types of numbers.</h3>

In Mathematics, there are six (6) common types of numbers and these include the following:

  • <u>Natural (counting) numbers:</u> these include 1, 2, 3, 4, 5, 6, .....114, ....560.
  • <u>Whole numbers:</u> these comprises all natural numbers and 0.
  • <u>Integers:</u> these are whole numbers that may either be positive, negative, or zero such as ....-560, ...... -114, ..... -4, -3, -2, -1, 0, 1, 2, 3, 4, .....114, ....560.
  • <u>Irrational numbers:</u> these comprises non-terminating or non-repeating decimals.
  • <u>Real numbers:</u> these comprises both rational numbers and irrational numbers.
  • <u>Rational numbers:</u> these comprises fractions, integers, and terminating (repeating) decimals such as ....-560, ...... -114, ..... -4, -3, -2, -1, -1/2, 0, 1, 1/2, 2, 3, 4, .....114, ....560.

This ultimately implies that, a rational fraction simply comprises a real number and it can be defined as a quotient which consist of two integers x and y.

<h3>What are restrictions?</h3>

In Mathematics, restrictions can be defined as all the real numbers that are not part of the domain because they produces a value of 0 in the denominator of a rational fraction.

In order to determine the restrictions for this rational fraction, we would equate the denominator to 0 and then solve:

23/7y;

7y = 0

y = 0/7

y ≠ 0.

Read more on restrictions here: brainly.com/question/10957518

#SPJ1

Complete Question:

State any restrictions on the variables 23/7y

4 0
2 years ago
preliminary sample of 100 labourers was selected from a population of 5000 labourers by simple random sampling. It was found tha
VladimirAG [237]

Answer:

n=\frac{0.4(1-0.4)}{(\frac{0.05}{1.96})^2}=368.79  

n=369

Step-by-step explanation:

1) Notation and definitions

X=40 number of the selected labourers opt for a new incentive scheme.

n=100 random sample taken

\hat p=\frac{40}{100}=0.4 estimated proportion of the selected labourers opt for a new incentive scheme.

p true population proportion of the selected labourers opt for a new incentive scheme.

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

2) Solution tot he problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical value would be given by:

z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.05 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

And replacing into equation (b) the values from part a we got:

n=\frac{0.4(1-0.4)}{(\frac{0.05}{1.96})^2}=368.79  

And rounded up we have that n=369

8 0
3 years ago
9/10 - 3/5<br> 1/2 - 1/8<br> 7/8- 2/3<br> 5/12- 1/4 <br> SUBTRACTING FRACTIONS &amp; MIXED NUMBERS
balu736 [363]

The first one is 1 1/5 I think

Step-by-step explanation:

9/10 - 3/5

9-3=6 10-5=5

6/5 6÷5= 1 1/5

5 0
3 years ago
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