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Verdich [7]
3 years ago
10

Someone please solve this

Mathematics
1 answer:
babymother [125]3 years ago
8 0
6,135.9 is the correct answer
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Using the Distributive Property, find the product of the expression 7(22) and then simplify.
Artyom0805 [142]
The answer is 3.........
6 0
3 years ago
Grandpa schmidt is 75 years old. this is 9 years less than seven times the age of junior schmidt. how old is junior
Ad libitum [116K]
Grandpa's age is 75 years
Seven times the age of junior = age of grandpa + 9 jears = 75 + 9 = 84 years
Hence, the age of junior will be 84 / 7 = 12 years. (Since 84 is seven times his age, you have to devide by seven).
--> Junior is 12 years old.

I hope I've been helpful, MarkV
3 0
3 years ago
If R = 25 cm and S = 7 cm, what is the length of T?
Levart [38]

Answer: 24cm

Step-by-step explanation:

R = 25 cm

S = 7 cm

T = ?

The square of equals to the addition of the square of S and the square of T.

R^2 = S^2 + T^2

25^2 = 7^2 + T^2

T^2 = 25^2 - 7^2

T^2 = 625 - 49

T =✓576

T = 24cm

8 0
3 years ago
What is the y-intercept for y+2= -3/4(x+4)
fiasKO [112]

The answer would be: -5

Heres how you solve it!

First, change the x into a 0 so it can be removed.

y+2= -3/4*4

Now with the GCF you can reduce the numbers with 4.

y+2= -3

Then move the 2 to the other side causing it to change its sign into a negative

y= -3-2

Since -3 and -2 are both negative it would be -5

y= -5

then you are left with your answer.

Hope this helps! :3

8 0
4 years ago
Evaluate the surface integral S F · dS for the given vector field F and the oriented surface S. In other words, find the flux of
Maru [420]

Parameterize S{/tex] by[tex]\vec s(u,v)=u\,\vec\imath+v\,\vec\jmath+(8-u^2-v^2)\,\vec k

with 0\le u\le1 and 0\le v\le1.

Take the normal vector to S to be

\vec s_u\times\vec s_v=2u\,\vec\imath+2v\,\vec\jmath+\vec k

Then the flux of \vec F across S is

\displaystyle\iint_S\vec F\cdot\mathrm d\vec S=\int_0^1\int_0^1\vec F(x(u,v),y(u,v),z(u,v))\cdot(\vec s_u\times\vec s_v)\,\mathrm du\,\mathrm dv

=\displaystyle\int_0^1\int_0^1(uv\,\vec\imath+v(8-u^2-v^2)\,\vec\jmath+u(8-u^2-v^2)\,\vec k)\cdot(2u\,\vec\imath+2v\,\vec\jmath+\vec k)\,\mathrm du\,\mathrm dv

=\displaystyle\int_0^1\int_0^1\bigg(2u^2v+(u+2v^2)(8-u^2-v^2)\bigg)\,\mathrm du\,\mathrm dv=\boxed{\frac{1553}{180}}

6 0
3 years ago
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