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Verdich [7]
3 years ago
10

Someone please solve this

Mathematics
1 answer:
babymother [125]3 years ago
8 0
6,135.9 is the correct answer
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Can you please explain how you did it. Thanks!
vivado [14]
Well first you would start by setting up with a proportion.
In total, the girls paid $54+$22= $76
Thus 1 sister contributed $54/$76=x/100
The other sister contributed $22/$76=x/76
For each proportion, cross-multiply and simplify to get the percentage. The percentage will be the x
5 0
3 years ago
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PLEASE HELP. graph the set of points which model is most appropriate for the set (-6,4)(-4,0)(-3,-2)(-1,-7)
SOVA2 [1]
A linear equation would be the best fit, but the last point (-1,-7) kinda messes it up. If the -7 would have been a -6 the line y=-2x-8 would fit perfectly.
7 0
3 years ago
Click on equation for a line that passes through coordinates (2, 1), (5, -1)
zheka24 [161]

Answer:

about -.66 x + 2.33

5 0
3 years ago
A simple random sample of 60 items resulted in a sample mean of 65. The population standard deviation is 14. a. Compute the 95%
bazaltina [42]

Answer:

The 95% confidence interval for the population mean is between 61.5 and 68.5.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.95}{2} = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.025 = 0.975, so z = 1.96

Now, find M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 1.96*\frac{14}{\sqrt{60}} = 3.5

The lower end of the interval is the sample mean subtracted by M. So it is 65 - 3.5 = 61.5

The upper end of the interval is the sample mean added to M. So it is 65 + 3.5 = 68.5

The 95% confidence interval for the population mean is between 61.5 and 68.5.

6 0
3 years ago
Read 2 more answers
Consider an airplane heading due east at 150 miles/hour relative to the air. The wind is blowing at 7.1 miles/hour at 45º south
sergij07 [2.7K]

We have

<span>Va(airplane)=150  East</span>

Vw(wind)=7.1 South East

<span>
</span><span>resulting vector R</span>

airplane

Vax=150    Vay=0   it only has component x 


Wind
Vwx=7.1*cos45=5.02

Vwy=7.1*sin45=-5.02 is negative because is South direction

 |R|=(Rx^2+Ry^2) ^0.5

Rx=150+5.02=155.02

Ry=0-5.02=-5.02

<span>|R|=155.10 miles/hour South East</span>

Determine angle θ

Rx=R*cos(θ)

<span>Cos(θ)=Rx/R</span> <span>Cos(θ)=155.02/155.10=0.9995</span>

 θ =arc cos Rx/R θ =1.8119 º

 Rx represents the component in the East direction of the resultant force. Your contribution is given by both, the force of the plane and the wind. The contribution of the wind makes the airplane's speed greater

 Ry represents the component in the South direction of the resulting force Its contribution is exclusive of the wind since the airplane has no component in this direction

 |R| the force resulting from the combined action of the force of the plane and the force of the wind

 θ represents the angle that forms the resultant force with respect to the x axis or east direction

5 0
2 years ago
Read 2 more answers
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