Answer:
The correct statement is:
On average, the height of a garden gnome varies 3.2 inches from the mean of 6 inches.
Step-by-step explanation:
We are given a data of 11 gardens as:
2 9 1 23 3 7 10 2 10 9 7
Now on removing the outlier i.e. 23 (since it is the very large value as compared to other data points) the entries are as follows:
x |x-x'|
2 4
9 3
1 5
3 3
7 1
10 4
2 4
10 4
9 3
7 1
Now mean of the data is denoted by x' and is calculated as:
Hence, Mean(x')=6
Now,
∑ |x-x'|=32
Now mean of the absolute deviation is:
This means that , On average, the height of a garden gnome varies 3.2 inches from the mean of 6 inches.
Answer:
<em>5</em><em> players participated in the tournament.</em>
Step-by-step explanation:
In a small chess tournament, 20 matches were played.
Let us assume that n number of players participated in the tournament
As in each game 2 players play, so the number of ways they can play is,
As they played 2 games with every other participant in the tournament.
So the total number of games is,
But it is given to be 20, so
As 
, so we get n=5.
Therefore, 5 players participated in the tournament.
Center c and a scale factor of 2
Answer:
133.33g
Step-by-step explanation:
Let the:
Mass of 1.2g/cm³ of liquid = x
Mass of 1.8g/cm³ of liquid = y
From our Question above, our system of equations is given as:
x + y = 400........ Equation 1
x = 400 - y
1.2 × x + 1.8 × y = 1.6 × 400
1.2x + 1.8y = 640..... Equation 2
We substitute, 400 - y for x in Equation 2
1.2(400 - y) + 1.8y = 640
480 - 1.2y + 1.8y = 640
- 1.2y + 1.8y = 640 - 480
0.6y = 160
y = 160/0.6y
y = 266.67 g
Solving for x
x = 400 - y
x = 400 - 266.67g
x = 133.33g
Therefore, the mass of the liquid of density 1.2g/cm³ is 133.33g
