Solve for y. 3y – 12 = –30 A. –6 B. 32 C. –2 D. 2
2 answers:
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Answer:
- <u>No, he can get an output of 0 with the second machine (function B) but he cannot get an output of 0 with the first machine (function A).</u>
Explanation
The way each machine works is given by the expression (function) inside it.
<u>1) </u><em><u>Function A</u></em>
To get an output of 0 with the function y = x² + 3, you must solve the equation x² + 3 = 0.
Since x² is zero or positive for any real number, x² + 3 will never be less than 3 (the minimum value of x² + 3 is 3). So, it is not possible to get an output of 0 with the first machine.
<u>2) </u><em><u>Function B</u></em>
Solve
So, he can get an output of 0 by using x = 4.