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rjkz [21]
3 years ago
8

Does anyone know how to solve this?

Mathematics
2 answers:
horsena [70]3 years ago
8 0

Answer:

x=360

Step-by-step explanation:

The inscribed angles theorem states that when given a circle, with an angle that has its vertex at the center of the circle, the measure of the angle is congruent to the measure of the arc surrounding it. One can apply this knowledge here by stating the following,

m

Substitute,

x=2\pi

However, this answer is in radians, it is the literal measurement. One must convert into degrees so that the answer fits the format of the question. The conversion rate to switch between radians and degrees is the following,

degree=\frac{\pi}{180}radians

Substitute,

degree=\frac{180}{\pi}(x)\\\\degree=\frac{180}{\pi}(2\pi)\\

Simplify,

degree=\frac{180*(2\pi)}{\pi}\\degree=360

Dmitry_Shevchenko [17]3 years ago
6 0

Answer:

x = 45°

Step-by-step explanation:

Given arc length = 2π cm

         Radius, r = 8 cm

      Arc \ Length = 2 \pi r (\frac{x}{360})

             2 \pi = 2 \pi \times 8 \frac{ x}{360}\\\\\frac{2 \pi}{16 \pi} = \frac{x }{ 360}\\\\\frac{1}{8} = \frac{x}{360}\\\\\frac{360}{8} = x\\\\x = 45^\circ

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natulia [17]

Answer: 4.5

<u>Step-by-step explanation:</u>

First, find the points of intersection by solving the system.

y = x² + 2x + 4

y = x + 6

Solve by substitution:

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Now, integrate from x = -2 to x = 1

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= \int\limits^1_2 {x+6-x^{2}-2x-4 } \,

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= (\frac{-1^{3}}{3} - \frac{1^{2}}{2}+2(1)) - (\frac{-(-2)^{3}}{3} - \frac{(-2)^{2}}{2}+2(-2))

= (\frac{-1}{3} - \frac{1}{2} +2) - (\frac{8}{3} -\frac{4}{2} -4)

= \frac{-9}{3} + \frac{3}{2} +6

= -3 + 1.5 + 6

= 4.5


3 0
3 years ago
I know it has to be b or d
densk [106]

It is C, however I might be wrong so you can visit this website.

Websites: https://www.varsitytutors.com/hotmath/hotmath_help/topics/converse-inverse-contrapositive

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valina [46]

Answer:

x = 4/5

Step-by-step explanation:

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5) Simplify

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6) Subtract x from both sides

   16x - x = x + 12 - x

7) Simplify

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8) Divide both sides by 15

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9) Simplify

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