The distance between Car A and car B,When Car A crosses the start line is:
distance =speed car B* time
distance=(15 m/s)(3 s)=45 m
Distance traveled by car A =x, (when the car B is at the same distance from the start line)
time of car A=t
x=10 m/st ⇒ x=10t (1)
Distance traveled by car B=x
time of car B=t-3
x=15(t-3) (2)
With the equations (1) and (2) we make a system of equations:
x=10t
x=15(t-3)
We solve this system of equations:
10t=15(t-3)
10t=15t-45
-5t=-45
t=-45 / -5
t=9
t-3=9-3=6
x=10 t=10 (9)=90
Answer: The time would be 9 seconds for Car A and 6 seconds for car B and the distance would be 90 meters.
Answer:
the answer is B.angle A and angle B
Answer:
D or last one
Step-by-step explanation:
Answer:
The answer to your question is Volume = (1/3)(x²)(x + 2)
Step-by-step explanation:
Data
length = x
height = x + 2
Volume = ?
Formula
Volume = 1/3Ab h
Process
1.- Calculate Ab
Ab = length x length
-Substitution
= (x)(x)
-Simplification
= x²
2.- Substitution
Volume = (1/3)(x²)(x + 2) or (1/3)(x³ + 2x²)
Answer: 11
Step-by-step explanation:Since the y coordinates are the same, the distance is the values between the x coordinates 6 - -5
6+5
11
