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3 years ago

Please help I really need it thx!!

Mathematics

2 answers:

VashaNatasha [74]3 years ago

6 0

Answer:

a- (0,6)

b- (2,8)

c- (6,7)

d- (3,4)

d- (5,2)

yKpoI14uk [10]3 years ago

6 0

Answer:

a- (0,6)

b- (2,8)

c- (6,7)

d- (3,4)

e- (5,2)

Step-by-step explanation:

All you need to do is go up to the letter and then from where the letter sits. look at the number to left and put it as the bottom number first and the number towards the left at the end like this ex: (8,2)

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Read 2 more answers

Please help me i need it -_-

Natasha2012 [34]

The answer to your question is option b

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3 years ago

Which ofnthe following shows the correct use of distributive property when solving 1/3(33-x)=135,2

madam [21]

Answer: OPTION C.

Step-by-step explanation:

The missing options are:

$A. (33 - x) = \frac{1}{3} * 135.2\\\\B. (\frac{1}{3} *33) - \frac{1}{3} x = \frac{1}{3} * 135.2\\\\C.(\frac{1}{3} * 33) - \frac{1}{3} x = 135.2\\\\D. (\frac{1}{3} * 33) + \frac{1}{3} x = 135.2$

In order to solve this exercise you need to remember the following:

1. The Distributive property states that:

$a(b+c)=ab+ac\\\\a(b-c)=ab-ac$

2. The multiplication of signs:

$(+)(+)=+\\(-)(-)=+\\(-)(+)=-\\(+)(-)=-$

In this case the exercise gives you the following equation:

$\frac{1}{3}(33-x)=135.2$

Since you need to solve for the variable "x" in order to find its value, the first step you must apply in the in the procedure is to eliminate the parentheses applying the Distributive property.

Then, you must multiply everyting inside the parentheses by $\frac{1}{3}$ .

Therefore,based on the explanation, you know that the correct use of the Distributive property is:

$\frac{1}{3}*33-\frac{1}{3}x=135.2$

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3 years ago

A certain circle can be represented by the following equation. x^2+y^2+6y-72=0 What is the center of this circle ?

jek_recluse [69]

Answer:

(0, -3)

Step-by-step explanation:

Here we'll rewrite x^2+y^2+6y-72=0 using "completing the square."

Rearranging x^2+y^2+6y-72=0, we get x^2 + y^2 + 6y = 72.

x^2 is already a perfect square. Focus on rewriting y^2 + 6y as the square of a binomial: y^2 + 6y becomes a perfect square if we add 9 and then subtract 9:

x^2 + y^2 + 6y + 9 - 9 = 72:

x^2 + (y + 3)^2 = 81

Comparing this to the standard equation of a circle with center at (h, k) and radius r,

(x - h)^2 + (y - k)^2 = r^2. Then h = 0, k = -3 and r = 9.

The center of the circle is (h, k), or (0, -3).

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3 years ago