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Umnica [9.8K]
3 years ago
8

Find f(3) if f(x)=-3x-6

Mathematics
1 answer:
Nikitich [7]3 years ago
6 0

Answer:

-3(3)-6=-15

Step-by-step explanation:

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Find the value of x and y. Triangle MNP = triangle TUS
xenn [34]

Answer:

x = 32, y = 51

Step-by-step explanation:

Since the triangles are congruent then corresponding sides and angles are congruent, that is

∠ U = ∠ N

∠ N = 180° - (142 + 24)° = 180° - 166° = 14° , then

2x - 50 = 14 ( add 50 to both sides )

2x = 64 ( divide both sides by 2 )

x = 32

and

NP = US

2x - y = 13

2(32) - y = 13

64 - y = 13 ( subtract 64 from both sides )

- y = - 51 ( multiply both sides by - 1 )

y = 51

3 0
3 years ago
7 x [(7+7) divided 7] =
galben [10]

BIDMAS

Step-by-step explanation:

FIRST DO 7+7÷7 AND TIMES THE ANSWER BY 7

6 0
3 years ago
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Nuetrik [128]

Answer:

250/30= 25/3

inverse of 25/3= 3/25

Step-by-step explanation:

3 0
3 years ago
Suppose that the functions and are defined for all real numbers as follows. r(x)=3x^(2) s(x)=2x write the expressions for (r-s)(
nirvana33 [79]
The expression for (r-s)(x) is found by subtracting s from r.  That difference is 3 x^{2} -2x.  The expression for (r+s)(x) is found by adding them, which is 3 x^{2} +2x.  Now we are told to evaluate (r*s)(x) which means they want us to multiply those and state the "new" expression that results.  (3 x^{2} )(2x)=6x^3.  There you go!
7 0
3 years ago
A 1400 kg car moving +13.7 m/s makes an elastic collision with a 3200 kg truck, initially at rest. What is the velocity of the c
Kamila [148]

Answer:

The velocity of the car after the collision is -5.36 m/s

Step-by-step explanation:

An elastic collision is an encounter between two bodies in which the total kinetic energy of the two bodies remains the same.

let the following:

m₁ = mass of the car = 1400 kg

m₂ = mass of the truck = 3200 kg

u₁ = velocity of the car before collision = 13.7 m/s

u₂ = velocity of the truck before collision = 0 m/s

v₁ = velocity of the car after collision

v₂ = velocity of the truck after collision

v₁ = [ u₁ * (m₁ - m₂) + u₂ * 2m₂ ]/ (m₁ + m₂)

   =  [ 13.7 * (1400 - 3200) + 0 * 2 * 3200 ]/ (1400 + 3200)

   = - 5.36 m/s

So, <u>the velocity of the car after the collision is -5.36 m/s</u>

7 0
3 years ago
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