Answer:
The answer is below
Step-by-step explanation:
The question is not complete. A complete question is in the form:
A letter is chosen at random from the letters of the word EXCELLENT. Find the probability that letter chosen is i) a vowel ii) a consonant.
Solution:
The total number of letters found in the word EXCELLENT = 9
i) The number of vowel letters found in the word EXCELLENT = {E, E, E} = 3
Hence, probability that letter chosen is a vowel = number of vowels / total number of letters = 3 / 9 = 1 / 3
probability that letter chosen is a vowel = 1/3 = 0.333 = 33.3%
ii) The number of consonant letters found in the word EXCELLENT = {X, C, L, L, N, T} = 6
Hence, probability that letter chosen is a consonant = number of consonant / total number of letters = 6 / 9 = 2 / 3
probability that letter chosen is a consonant = 2/3 = 0.667 = 66.7%
Answer:
Coordinates of Q 
Option D is correct option.
Step-by-step explanation:
We are given:
K is the midpoint of PQ
Coordinates of P = (-9,-4)
Coordinates of K = (-1,6)
We need to find coordinates of Q
We will use the formula of midpoint: 
We are given midpoint K and
the coordinates of P we need to find
the coordinates of Q.

Now, we can write

So, we get coordinates of Q 
Option D is correct option.
X + 4x = 40
5x = 40
5x/5 = 40/5
x = 8
1x 8 = 8
4x 8 = 32
Check=
8 + 32 = 40
The numbers are 8 and 32