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Pavel [41]
3 years ago
12

Which equation represents a line which is perpendicular to the line y = 4/3x – 7?

Mathematics
1 answer:
Dafna1 [17]3 years ago
3 0

Answer:

I believe this question should have several options or else you can simply name a any equation that satisfy the following:

Step-by-step explanation:

since the line is perpendicular to y = 4/3x - 7, the products of their slopes will be = -1.

so, slope x 4/3 = -1

slope = -3/4

any equation that has gradient/slope = -3/4 would be correct

Topic: coordinate geometry

If you like to venture further, feel free to check out my insta (learntionary). It would be best if you could give it a follow. I'll be constantly posting math tips and notes! Thanks!

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Which ratio is equivalent to 24/56?
Nostrana [21]
<span>24/56
= 3/7

hope it helps</span>
4 0
3 years ago
Read 2 more answers
Find perimeter of rectangle when length = 4.6m and breadth = 360cm​
ivann1987 [24]

Answer:

16.4 m²

Step-by-step explanation:

length = 4.6 m

breadth = 360 cm = 360 ÷ 100 = 3.6 m

Perimeter = 2*(l + b)

                 = 2 * ( 4.6 + 3.6)

                 = 2 * 8.2

                  = 16.4 m²

7 0
2 years ago
Read 2 more answers
1. Questions 1 and 2 refer to the figure shown.
sweet [91]
Answer: b. segment TX = 16 m.
3 0
3 years ago
Plz help me!!!
Nadya [2.5K]
To solve this we are going to use the exponential function: f(t)=a(1(+/-)b)^t
where
f(t) is the final amount after t years
a is the initial amount
b is the decay  or grow rate rate in decimal form
t is the time in years

Expression A 
f(t)=624(0.95)^{4t}
Since the base (0.95) is less than one, we have a decay rate here.
Now to find the rate b, we are going to use the formula: b=|1-base|*100%
b=|1-0.95|*100%
b=0.05*100%
b=5%
We can conclude that expression A decays at a rate of 5% every three months.

Now, to find the initial value of the function, we are going to evaluate the function at t=0
f(t)=624(0.95)^{4t}
f(0)=624(0.95)^{0t}
f(0)=624(0.95)^{0}
f(0)=624(1)
f(0)=624
We can conclude that the initial value of expression A is 624.

Expression B
f(t)=725(1.12)^{3t}
Since the base (1.12) is greater than 1, we have a growth rate here.
To find the rate, we are going to use the same equation as before:
b=|1-base|*100%
b=|1-1.12|*100
b=|-0.12|*100%
b=0.12*100%
b=12%
We can conclude that expression B grows at a rate of 12% every 4 months.

Just like before, to find the initial value of the expression, we are going to evaluate it at t=0
f(t)=725(1.12)^{3t}
f(0)=725(1.12)^{0t}
f(0)=725(1.12)^{0}
f(0)=725(1)
f(0)=725
The initial value of expression B is 725.

We can conclude that you should select the statements:
- Expression A decays at a rate of 5% every three months, while expression B grows at a rate of 12% every fourth months. 

- Expression A has an initial value of 624, while expression B has an initial value of 725.

8 0
2 years ago
Please help!! I don’t know what i’m doing at all
Shkiper50 [21]

Answer:

53 + 3g ≤ 65, g ≤ 4

Step-by-step explanation:

To solve for g:

53 + 3g ≤ 65

First, subtract 53 from both sides.

53 - 53 + 3g ≤ 65 - 53

=> 3g ≤ 12

Divide 3 by both sides

=> 3g / 3 ≤ 12 /3

=> g ≤ 4

Therefore, g ≤ 4

Hope this helps :)

8 0
3 years ago
Read 2 more answers
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