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Digiron [165]
3 years ago
12

I need help............,only question no.12​

Mathematics
1 answer:
rusak2 [61]3 years ago
5 0

Answer:

12. Please find attached the required plot created with MS Excel

Step-by-step explanation:

12. The points are given in their <em>x </em>and <em>y</em>-coordinates as follows;

(-2, 5), and (5, 2)

To plot the points on a graph, MS Excel plot function can be used as follows;

1) We enter the <em>x </em>and <em>y-</em>values of the first point, side by side in cells on the Excel spreadsheet

We enter the <em>x </em>and <em>y-</em>values of the second point, beneath the first point on the spreadsheet as follows;

\left | \begin{array}{ccc}-2&|&5\\5&|&2\end{array}  \right|

2) The four cells are selected and from the Insert menu within the Chart group, the Scatter (x, y) chart is selected

3) The plot created with MS Excel is attached

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Please SHOW WORK, will mark brainlist if correct
riadik2000 [5.3K]

Answer:

\huge\boxed{\sf \frac{x+3}{x-3}}

Step-by-step explanation:

\displaystyle = \frac{x+7}{x^2+4x-21} \div \frac{x+5}{x^2+8x+15} \\\\Apply \ mid-term \ break\\\\= \frac{x+7}{x^2 +7x-3x-21} \div \frac{x+5}{x^2 +3x+5x+15} \\\\= \frac{x+7}{x(x+7)-3(x+7)} \div \frac{x+5}{x(x+3)+5(x+3)} \\\\Taking \ (x+3) \ and \ (x+7) \ common\\\\= \frac{x+7}{(x-3)(x+7)} \div \frac{x+5}{(x+3)(x+5)} \\\\= \frac{1}{x-3} \div \frac{1}{x+3} \\\\= \frac{1}{x-3} * (x+3)\\\\= \frac{x+3}{x-3} \\\\\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>
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