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3 years ago

3y = 26 -5x 6x + 7 y = 21

1 answer:

5 0

m ≥ 5x-3 the best way for us to use the same as a huge forest is to add the main points to a fierce to be a better to use of the letters are the first time in a way she will not on the line 4x she will not on the line 4x and I will be restored.People's the process for my next course as the stirrup will not on the line 4x and the things that I have to do the work I did to myself to work with the People's team and

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What's the slope-intercept form that passes through the points (0, -1) and (1, 5)?

Rzqust [24]

Answer:

Step-by-step explanation:

$\bold{slope\, (m)=\dfrac{change\ in\ Y}{change\ in\ X}=\dfrac{y_2-y_1}{x_2-x_1}}$

(0, -1) ⇒ x₁ = 0, y₁ = -1

(1, 5) ⇒ x₂ = 1, y₂ = 5

So the slope:

$\bold{m=\dfrac{5+1}{1-0}=\dfrac{6}{1}=6}$

The slope-intercept form of the equation of line is y = mx + b, where m is the slope and b is the y-intercept of the line.

(0, -1) ⇒ x₀ = 0, y₀ = -1 ⇒ b = -1

Therefore:

y = 6x - 1 ← the slope-intercept form of the equation

5 0

3 years ago

Approximately 45% of films are rated R if 850 films were recently rated how many were rated R

amm1812

Answer:

382.5?????

Step-by-step explanation:

because 850×45% its that

6 0

3 years ago

Two trains 150 miles apart are traveling toward each other along the same track. The first train goes 60 miles per hour; the sec

Nataly_w [17]

Answer:

120 miles

Step-by-step explanation:

Distance = 150 miles

train 1 = 60 mph

train 2 = 90 mph

directions of trains = towards each other

Time to meet = 150/(60+90) = 150 miles / 150 mph = 1 hour

Speed of fly = 120 mph

Since fly has been flying for one hour, it travelled 120 miles.

3 0

3 years ago

Find the length of the third side. If necessary, round to the nearest tenth.<br> 30<br> 18

grigory [225]

Answer:

Step-by-step explanation:

use Pythagoras theorem

a^2 + b^2 = c^2

18^2+b^2=30^2

b^2 = 30^2 - 18^2

b = √576 =24

8 0

2 years ago

Help! Prove the equality<br><br>arccos √(2/3) - arccos (1+√6)/(2*√3) = π/6

stealth61 [152]

Answer:

<em>Proof in the explanation</em>

Step-by-step explanation:

<u>Trigonometric Equalities</u>

Those are expressions involving trigonometric functions which must be proven, generally working on only one side of the equality

For this particular equality, we'll use the following equation

$\displaystyle cos(x-y)=cos\ x\ cos\ y+sin\ x\ sin\ y$

The equality we want to prove is

$\displaystyle arccos\ \sqrt{\frac{2}{3}}-arccos\left(\frac{1+\sqrt{6}}{2\sqrt{3}}\right)=\frac{\pi}{6}$

Let's set the following variables:

$\displaystyle x=arccos\ \sqrt{\frac{2}{3}},\ y=arccos(\frac{1+\sqrt{6}}{2\sqrt{3}})$

And modify the first variable:

$\displaystyle x=arccos\ \frac{\sqrt{6}}{3}}=>\ cos\ x= \frac{\sqrt{6}}{3}}$

Now with the second variable

$\displaystyle y=arccos\ \frac{1+\sqrt{6}}{2\sqrt{3}}=>cos\ y=\frac{1+\sqrt{6}}{2\sqrt{3}}=\frac{\sqrt{3}+3\sqrt{2}}{6}$

Knowing that

$sin^2x+cos^2x=1$

We compute the other two trigonometric functions of X and Y

$\displaystyle sin \ x=\sqrt{1-cos^2\ x}=\sqrt{1-(\frac{\sqrt{6}}{3})^2}=\sqrt{1-\frac{6}{9}}=\frac{\sqrt{3}}{3}$

$\displaystyle sin\ y=\sqrt{1-cos^2y}=\sqrt{1-\frac{(\sqrt{3}+3\sqrt{2})^2}{36}}}$

$\displaystyle sin\ y=\sqrt{\frac{36-(3+6\sqrt{6}+18)}{36}}=\sqrt{\frac{15-6\sqrt{6}}{36}}$

Computing

$15-6\sqrt{6}=(3-\sqrt{6})^2$

Then

$\displaystyle sin\ y=\frac{3-\sqrt{6}}{6}$

Now we replace all in the first equality:

$\displaystyle cos(x-y)=\frac{\sqrt{6}}{3}.\frac{\sqrt{3}+3\sqrt{2}}{6}+\frac{\sqrt{3}}{3}.\frac{3-\sqrt{6}}{6}$

$\displaystyle cos(x-y)=\frac{3\sqrt{2}+6\sqrt{3}}{18}+\frac{3\sqrt{3}-3\sqrt{2}}{18}$

$\displaystyle cos(x-y)=\frac{9\sqrt{3}}{18}=\frac{\sqrt{3}}{2}=cos\ \pi/6$

Thus, proven

5 0

3 years ago