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just olya [345]
3 years ago
13

The spinner of the compass is two congruent isosceles triangles connected by their bases as shown in the diagram. The base of ea

ch of these triangles is 2 centimeters and the legs are 5 centimeters.
If the metal used to construct the spinner costs $13.25 per square centimeter, how much will it cost to make this part of the compass? Round to the nearest cent.

Cost =
Mathematics
2 answers:
kirill [66]3 years ago
7 0

Answer:

$ 129.82 because it is to the nearest cent

a_sh-v [17]3 years ago
6 0

Answer:

fff

Step-by-step explanation:

By pythagorean theorum we calculate the height:

\sqrt{5^2-1^2}

=\sqrt{24} = height of triangle

area of triangle = base * height

area = 2*\sqrt{24}

There are two triangles so:

2*2*\sqrt{24}=4\sqrt{24}

Multiply this by 13.25 to get total cost:

=$259.65

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2+363892917382827363
pentagon [3]

Answer:

363892917382827365

Step-by-step explanation:

thats how one adds

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3 years ago
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Explain why the rearranged expression is easier to work with
Alex17521 [72]
Where is the expression?
7 0
3 years ago
For the functions f(x)=2x^2+3x+9 and g(x)=−3x+10 find (f⋅g)(x) and (f⋅g)(1)
pashok25 [27]

Step-by-step explanation:

f(x)=2x²+3x+9

g(x) = - 3x + 10

In order to find (f⋅g)(1) first find (f⋅g)(x)

To find (f⋅g)(x) substitute g(x) into f(x) , that's for every x in f (x) replace it by g (x)

We have

(f⋅g)(x) = 2( - 3x + 10)² + 3(- 3x + 10) + 9

Expand

(f⋅g)(x) = 2( 9x² - 60x + 100) - 9x + 30 + 9

= 18x² - 120x + 200 - 9x + 30 + 9

Group like terms

(f⋅g)(x) = 18x² - 120x - 9x + 200 + 30 + 9

(f⋅g)(x) = 18x² - 129x + 239

To find (f⋅g)(1) substitute 1 into (f⋅g)(x)

That's

(f⋅g)(1) = 18(1)² - 129(1) + 239

= 18 - 129 + 239

We have the final answer as

<h3>(f⋅g)(1) = 128</h3>

Hope this helps you

3 0
4 years ago
Solve for x and y in the system of equation<br>3x²+4y=17 <br>2x²+5y=2<br>I'll mark brainliest​
Novay_Z [31]

Answer:

x=\pm \sqrt{11} \\y=-4.

Step-by-step explanation:

\left \{ {{3x^2+4y=17} \atop {2x^2+5y=2}} \right. \\\\Then\\\\\left \{ {{2 \times (3x^2+4y)=2 \times 17} \atop {3\times(2x^2+5y)=3\times2}} \right. \\\\\left \{ {{6x^2+8y=34 \quad (1)} \atop {6x^2+15y=6\quad (2)}} \right.\\\\(1)-(2) \Rightarrow -7y=28 \Rightarrow y =-4.\\Since \: \:  2x^2+5y=2 \Rightarrow 2x^2=2-5y\\\Rightarrow 2x^2=2+20=22\\\Rightarrow x^2=22:2=11\\\Rightarrow x=\pm \sqrt{11}.

7 0
3 years ago
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pentagon [3]

Answer:

I think Substitution

Step-by-step explanation:

Because x is already solved for in the second equation.

6 0
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