Answer:
its 0.163 g
Explanation:
From the total pressure and the vapour pressure of water we can calculate the partial pressure of O2
PO 2 =P t −P H 2 O
= 760 − 22.4
= 737.6 mmHg
From the ideal gas equation we write.
W= RT/PVM = (0.0821Latm/Kmol)(273+24)K(0.974atm)(0.128L)(32.0g/mol/) =0.163g
Answer:
Explanation
Let, Wavelength = W,
Given, frequency (f) = 50 Hz, wave velocity (V) = 342 m/s
We know, V = f × W
=> 342 = 50 × W
=> W = 342/50 metre
=> W = 6.84 metre
Answer:
See explanation
Explanation:
Now we have, the graph attached.the stable disintegration product of C-14 is N-14.
Then;
Since the mass of C-14 originally present is 64g, at a time t= 17100 years, we will have;
N/No = (1/2)^t/t1/2
N = mass of C-14 at time t
No= mass C-14 originally present
t = time taken for N amount of C-14 to remain
No = mass of C-14 originally present
t1/2 = half life of C-14
N/64 = (1/2)^17,100/5730
N/64 = (1/2)^3
N/64 = 1/8
8N = 64
N = 8 g
<h2>Hello!</h2>
The answer is: cold, rising air.
<h2>
Why?</h2>
The high-pressure areas are at the poles due to the cold rising air. It's known that the cold air is more sense that the warm air because the warm gases molecules are more separated during the gas, is warm, which make it less dense than cold air.
Due to the form of our planet and the location of the poles, the cold air rises while the warm air down around the tropics and rise again to the poles (getting cold while it's getting closer to the poles).
High-pressure at poles is also caused because the solar radiation is higher at the equator than at the poles.
Have a nice day!
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