Base your answers to questions 74 through 76 on the data table below and on your knowledge of Earth

Chemistry

1 answer:

Serjik [45]3 years ago

6 0

Answer:

See explanation

Explanation:

Now we have, the graph attached.the stable disintegration product of C-14 is N-14.

Then;

Since the mass of C-14 originally present is 64g, at a time t= 17100 years, we will have;

N/No = (1/2)^t/t1/2

N = mass of C-14 at time t

No= mass C-14 originally present

t = time taken for N amount of C-14 to remain

No = mass of C-14 originally present

t1/2 = half life of C-14

N/64 = (1/2)^17,100/5730

N/64 = (1/2)^3

N/64 = 1/8

8N = 64

N = 8 g

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