Answer:
0.0702J/g°C the specific heat capacity of the metal.
Explanation:m
where,
Q = heat absorbed by metal = 186.75 J
= Mass of metal= 19 g
= Initial temperature of metal = 
=Final temperature of metal = 
= specific heat of metal= ?
0.0702J/g°C the specific heat capacity of the metal.
Answer:
The final temperature of the water is 28.0 °C
Explanation:
Step 1: Data given
Mass of liquid water = 10.0 grams
Temperature = 23.0 °C
Heat absorbed = 209 Joules
Since heat was absorbed by the water, you must have a positive value for
Δ
T
Step 2: Calculate final temperature
q = m*c* ΔT
⇒ with m = the mass of the water = 10.0 grams
⇒ with c = the specific heat of water = 4.184 J/g°C
⇒ with ΔT = The change in temperature = T2 - T1 = T2 - 23.0 °C
⇒ with q = the heat absorbed = 209 Joule
209 = 10.0 * 4.184 * ΔT
ΔT = 5
ΔT = 5 = T2 - 23
T2 = 28 °C
The final temperature of the water is 28.0 °C
Henry law:
P = KC
P = solvent vapour pressure
K = Henry constant
C = conc of solute
So, 0.2 = 773 C
so, C = 0.2 / 773 = 2.5 x 10^{-4} molal
