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3 years ago

Base your answers to questions 74 through 76 on the data table below and on your knowledge of Earth

Chemistry

1 answer:

Serjik [45]3 years ago

6 0

Answer:

See explanation

Explanation:

Now we have, the graph attached.the stable disintegration product of C-14 is N-14.

Then;

Since the mass of C-14 originally present is 64g, at a time t= 17100 years, we will have;

N/No = (1/2)^t/t1/2

N = mass of C-14 at time t

No= mass C-14 originally present

t = time taken for N amount of C-14 to remain

No = mass of C-14 originally present

t1/2 = half life of C-14

N/64 = (1/2)^17,100/5730

N/64 = (1/2)^3

N/64 = 1/8

8N = 64

N = 8 g

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sammy [17]

4V is the necessary voltage to power the electrolysis of molten sodium chloride.

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For this electrolysis to take place, the battery needs to supply more than 4 volts. The only means to obtain pure sodium metal is by this reaction, which also serves as a significant source of chlorine gas generation. Swimming pools and other surfaces are frequently cleaned and disinfected with chlorine gas.

Learn more about sodium chloride here;

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3 years ago

In the following reaction, which species is reduced? Au(s) + 3NO3-(aq) + 6H+(aq) → Au3+(aq) + NO(g) + 3H2O (l) H+ N+5 O2- H2O Au

weqwewe [10]

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Given the reaction equation;

Au(s) + 3NO3-(aq) + 6H+(aq)→Au3+(aq) + 3NO2(g) + 3H2O (l).

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Since reduction has to do with a decrease in oxidation number, it follows that NO3- was reduced in the reaction.

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