Here’s the math for your answer, which is 3.3 L HCl
Answer:
I don't understand what you are asking
Answer:
119.5 J
Explanation:
First we <u>calculate the temperature difference</u>:
- ΔT = 100 °C - 50 °C = 50 °C
Then we can <u>calculate the heat released</u> by using the following formula:
Where q is the heat, Cp is the specific heat, ΔT is the temperature difference and m is the mass.
We <u>input the data</u>:
- q = 0.239 J/g°C * 50 °C * 10.0 g
Answer:
18 moles
Explanation:
Here the combustion of one mole of glucose ----> carbon dioxide + water, releases 2870 kilojoules / moles.
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With one contraction cycle requiring 55 kilojoules,
2870 / 55 ≈ 52.18
And with the efficiency being 35 percent,
52.1818..... * 0.35 = ( About ) 18 moles
<u><em>Hope that helps!</em></u>