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givi [52]
3 years ago
6

Find the difference between8/15 and 2/3 Show all calculations in your final answer.

Mathematics
1 answer:
kherson [118]3 years ago
3 0

Answer:

  • \frac{8}{15}-\left(\frac{-2}{3}\right)=\frac{6}{5}          

Step-by-step explanation:

  • Let the value of a number 'a' be = 8/15
  • Let the value of a number 'b' be = 2/3

The difference between the two numbers can be calculated by subtracting the numbers

a-b=\frac{8}{15}-\left(\frac{-2}{3}\right)

\mathrm{Remove\:parentheses}:\quad \left(a\right)=a

         =\frac{8}{15}-\frac{-2}{3}

\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{-a}{b}=-\frac{a}{b}

          =\frac{8}{15}-\left(-\frac{2}{3}\right)

\mathrm{Apply\:rule}\:-\left(-a\right)=a

          =\frac{8}{15}+\frac{2}{3}

\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}

          =\frac{8+10}{15}

          =\frac{18}{15}

\mathrm{Cancel\:the\:common\:factor:}\:3

           =\frac{6}{5}

Thus,

  • \frac{8}{15}-\left(\frac{-2}{3}\right)=\frac{6}{5}                    
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\star{ \text{ \: Length \: of \: a \: rectangle \: ( \: l \: ) \:  =  \: 3xy}}

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\underline{ \sf{Finding \: the \: area \: of \: a \: rectangle \: }}

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\dashrightarrow{ \sf{ (3 * 14)  \: * \: x \: * \:  {x}^{2}  \: * \: y \: * \: y}}

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\text{step \: 2 \:  : Add \: the \: power \: of \: the \: variables \: with \: same \: base.}

\dashrightarrow{ \sf{42* {x}^{1 + 2} \:  * \:  {y}^{1 + 1} }}

\dashrightarrow{ \sf{42 {x}^{3}  {y}^{2} }}

The area of a rectangle = 42 x³ y²

\text{Hope \: I \: helped!}

\text{Best \: wishes!}

~\text{TheAnimeGirl}

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