Ask question

Ask question

All categories

2 years ago

10

Evaluate the following expression: (-5)(6) + (-6) ÷ (-3). Remember to show your work

2 answers:

pogonyaev2 years ago

8 0

Answer: =-28

Step-by-step explanation: Hope this help :D

Vinil7 [7]2 years ago

7 0

Answer:

-28

Step-by-step explanation:

(-5)(6) + (-6) ÷ (-3) =

-30 + (-6) ÷ (-3) =

-30 + 2 =

-28

<em>Hope that helps! :)</em>

<em></em>

<em>-Aphrodite</em>

You might be interested in

What is (30 1/9 + 4 1/3) - 19 5/6

weqwewe [10]

14 11/18
I got this answer by doing 30 1/9 + 4 1/3= 34 4/9
Now I subtracted 34 4/9 by 19 5/6 to get the answer 14 11/18
TIP: When adding/subtracting/multiplying/dividing mixed numbers change them to an improper fraction first by multiplying the denominator and the whole number then adding the numerator

5 0

3 years ago

What is the fraction for 0.2

Olenka [21]

1/5 this is the closest answer i can think of

3 0

2 years ago

Read 2 more answers

I will mark as the brainiest if you get this correct<br> thx so much xxx

fgiga [73]

360 g plain flour
3 eggs
900 ml milk

4 0

2 years ago

Estimate 13.23 - 2.570 by first rounding each number to the nearest tenth.

Temka [501]

Answer:

7

Step-by-step explanation:

13.23 = 10

2.570= 3

10-3=7

6 0

2 years ago

Read 2 more answers

3x^2+kx=-3 What is the value of K will result in exactly one solution to the equation?

Scorpion4ik [409]

Answer:

For k = 6 or k = -6, the equation will have exactly one solution.

Step-by-step explanation:

Given a second order polynomial expressed by the following equation:

$ax^{2} + bx + c, a\neq0$ .

This polynomial has roots $x_{1}, x_{2}$ such that $ax^{2} + bx + c = (x - x_{1})*(x - x_{2})$ , given by the following formulas:

$x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}$

$x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}$

$\bigtriangleup = b^{2} - 4ac$

If $\bigtriangleup = 0$ , the equation has only one solution.

In this problem, we have that:

$3x^{2} + kx + 3 = 0$

So

$a = 3, b = k, c = 3$

$\bigtriangleup = b^{2} - 4ac$

$\bigtriangleup = k^{2} - 4*3*3$

$\bigtriangleup = k^{2} - 36$

We will only have one solution if $\bigtriangleup = 0$ . So

$\bigtriangleup = 0$

$k^{2} - 36 = 0$

$k^{2} = 36$

$k = \pm \sqrt{36}$

$k = \pm 6$

For k = 6 or k = -6, the equation will have exactly one solution.

3 0

2 years ago