(1) Outcomes
(2) Permutation
(3) Tree Diagram
(4) Counting Principle
(5) Combination
(6) Factorial
(7) Addition Principle of Counting
(8) Multiplication Principle of Counting
<em>Hope this helps</em>
<em>-Amelia The Unknown</em>
\left(\mathrm{Decimal:\quad }x=-0.75\right)
hope it helps :P
The drawing shows a circle, with the two lines forming a cross assumed to be perpendicular to each other, so this is most likely to be a square, as the four points at which the perpendicular lines intersect with the circle can be connected to form a square.
We would need 3 points for an equilateral triangle, 5 for a pentagon, and 6 for a hexagon, which do not fit the current steps.
Answer:
A and E
Step-by-step explanation:
substitute and odd number into every equation :)
