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tatyana61 [14]
3 years ago
6

Find the value of x in the triangle shown below 5.7 5 x 70 5

Mathematics
1 answer:
jonny [76]3 years ago
7 0

Answer:

55

Step-by-step explanation:

Right on edge

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In this triangle, the product of sin B and tan C is<br> and the product of sin Cand tan B is
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Answer:

\frac{c}{a} and \frac{b}{a}

Step-by-step explanation:

sinB = \frac{opposite}{hypotenuse} = \frac{AC}{BC} = \frac{b}{a}

tanC = \frac{opposite}{adjacent} = \frac{AB}{AC} = \frac{c}{b}

Thus

sinB tanC = \frac{b}{a} × \frac{c}{b} ( cancel b on numerator/ denominator )

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---------------------------------------------------------------------------

sinC = \frac{opposite}{hypotenuse} = \frac{AB}{BC} = \frac{c}{a}

tanB = \frac{opposite}{adjacent} = \frac{AC}{AB} = \frac{b}{c}

Thus

sinC tanB = \frac{c}{a} × \frac{b}{c} ( cancel c on numerator/ denominator )

                 = \frac{b}{a}

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