A=162sq......... bless up
Answer:
EF =
≈ 5.83
Step-by-step explanation:
Calculate EF using the distance formula
d = 
with (x₁, y₁ ) = E(1, 3) and (x₂, y₂ ) = F(- 2, 8)
EF = 
= 
= 
=
≈ 5.83 ( to 2 dec. places )
<h2><u>
Answer with explanation</u>
:</h2>
Let
be the population mean.
As per given , we have

Since the alternative hypothesis is right-tailed , so the test is a right-tailed test.
Also, population standard deviation is given
, so we perform one-tailed z-test.
Test statistic : 
, where
= Population mean
= Population standard deviation
n= sample size
= Sample mean
For n= 18 ,
,
,
, we have

P-value (for right tailed test): P(z>2.12) = 1-P(z≤ 2.12) [∵ P(Z>z)=1-P(Z≤z)]\
=1- 0.0340=0.9660
Decision : Since P-value(0.9660) > Significance level (0.01), it means we are failed to reject the null hypothesis.
[We reject null hypothesis if p-value is larger than the significance level . ]
Conclusion : We do not have sufficient evidence to show that the goal is not being met at α = .01 .
0, 3
- 10, 15
= -10, -12
therefore, the slope is 6/5, and the intercept (c) is as supplied, 3.
the equation, y=mx+c or y = a + bx, can be applied here where m or b = 6/5, and a or c = 3.
therefore the equation is y=6/5x+3.
To test this, you can put in y = 10(6/5)+3, which spits out y = 15. This way we know it *should* work.