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NNADVOKAT [17]
2 years ago
9

Tell whether each integer is prime, composite or neither

Mathematics
1 answer:
melamori03 [73]2 years ago
6 0
1.; 3.; 5. are prime numbers.
All others are composite numbers.
Good luck!
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Which number is larger? (1 mark)<br><br> 0.67 or<br> 2/3
KengaRu [80]

Answer:

0.67

Step-by-step explanation:

2/3= to 0.66 which means 0.67 would be technally larger than 0.66

8 0
2 years ago
Miss Trejo ran 120 yard. What are equivalent distance to how far she ran?
erastova [34]

Answer: 360 feet, or 3/44 of a mile

Step-by-step explanation: One yard is 3 feet, and 1760 yards are in a mile

7 0
2 years ago
Let a be an irrational number. Is 1/a rational or irrational
Marianna [84]

<u>1 is a rational number</u> because 1 can go into 1 when dividing. <u>Irrational numbers are mostly decimals. </u>

7 0
3 years ago
Read 2 more answers
Triangles A and B are similar. A has side lengths 2, 4, and 6. B has corresponding side lengths ???, 16, and 24
ZanzabumX [31]

Answer:

The length of A will be 8 as

The ratio between the sides are 4:1

Since Side is 2 therefore side A=2*4

=8

Hope u got your answer..

8 0
2 years ago
A worker was paid a salary of $10,500 in 1985. Each year, a salary increase of 6% of the previous year's salary was awarded. How
Mazyrski [523]
Note that 6% converted to a decimal number is 6/100=0.06. Also note that 6% of a certain quantity x is 0.06x.

Here is how much the worker earned each year:


In the year 1985 the worker earned <span>$10,500. 

</span>In the year 1986 the worker earned $10,500 + 0.06($10,500). Factorizing $10,500, we can write this sum as:

                                            $10,500(1+0.06).



In the year 1987 the worker earned

$10,500(1+0.06) + 0.06[$10,500(1+0.06)].

Now we can factorize $10,500(1+0.06) and write the earnings as:

$10,500(1+0.06) [1+0.06]=$10,500(1.06)^2.


Similarly we can check that in the year 1987 the worker earned $10,500(1.06)^3, which makes the pattern clear. 


We can count that from the year 1985 to 1987 we had 2+1 salaries, so from 1985 to 2010 there are 2010-1985+1=26 salaries. This means that the total paid salaries are:

10,500+10,500(1.06)^1+10,500(1.06)^2+10,500(1.06)^3...10,500(1.06)^{26}.

Factorizing, we have

=10,500[1+1.06+(1.06)^2+(1.06)^3+...+(1.06)^{26}]=10,500\cdot[1+1.06+(1.06)^2+(1.06)^3+...+(1.06)^{26}]

We recognize the sum as the geometric sum with first term 1 and common ratio 1.06, applying the formula

\sum_{i=1}^{n} a_i= a(\frac{1-r^n}{1-r}) (where a is the first term and r is the common ratio) we have:

\sum_{i=1}^{26} a_i= 1(\frac{1-(1.06)^{26}}{1-1.06})= \frac{1-4.55}{-0.06}= 59.17.



Finally, multiplying 10,500 by 59.17 we have 621.285 ($).


The answer we found is very close to D. The difference can be explained by the accuracy of the values used in calculation, most important, in calculating (1.06)^{26}.


Answer: D



4 0
2 years ago
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