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3 years ago

Which equation is a linear function y = 2/x + 3 y = x/2 - 5 y = 2 ^ z - 1 y = x ^ 2 + 7

Mathematics

2 answers:

stich3 [128]3 years ago

6 0

Answer:

hello how do i work this app im new

Step-by-step explanation:

Free_Kalibri [48]3 years ago

3 0

Answer: y = x ^ 2 + 7

Step-by-step explanation: trust me

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Which of the following is equivalent to -21(6 - 71)?

Wittaler [7]

Answer: D

Step-by-step explanation:

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3 years ago

The perimeter of a rectangle is 215 feet. The short sides are each 24 feet long, but the lengths of the long sides are unknown.

Nataly_w [17]

Answer:

2 ( 24 ) + 2 a = 215

Step-by-step explanation:

Perimeter of the rectangle is 215 feet, the short sides are 24 feet long and we need to work out the long sides (we will call a long side 'a') so,

24 + 24 + a + a = 215

6 0

3 years ago

Read 2 more answers

A vat of milk has spilled on a tile floor. The milk flow can be expressed with the function r(t) = 4t, where t represents time i

Likurg_2 [28]

R(t) = 4t
A(r) = π(r^2)

a) A(t) = A[r(t)] = π[r(t)]^2 = π[4t]^2 = 16π(t^2)

b) t = 4,

A(4) = 16*3.14*(16)^2 = 12,861.44

3 0

3 years ago

For the month of November in a certain city, 88% of the days are cloudy. Also in the month of November in the same city, 54%

Gnoma [55]

Answer:

There is a 61.36% probability that a randomly selected day in November will be foggy if it is cloudy.

Step-by-step explanation:

We have these following probabilities:

An 88% probability that the day is cloudy.

An 54% probability that the day is both foggy and cloudy.

What is the probability that a randomly selected day in November will be foggy if it is cloudy?

This is the percentage of days that are cloudy and foggy divided by those that are cloudy. So:

$P = \frac{0.54}{0.88} = 0.6136$

There is a 61.36% probability that a randomly selected day in November will be foggy if it is cloudy.

4 0

3 years ago

Pleeeeese help me as fast as you can!!!

Aleonysh [2.5K]

Answer:

A. $y=3x-10$

C. $y+6=3(x-15)$

Step-by-step explanation:

Given:

The given line is $6x+18y=5$

Express this in slope-intercept form $y=mx+b$ , where m is the slope and b is the y-intercept.

$6x+18y=5\\18y=-6x+5\\y=-\frac{6}{18}x+\frac{5}{18}\\y=-\frac{1}{3}x+\frac{5}{18}$

Therefore, the slope of the line is $m=-\frac{1}{3}$ .

Now, for perpendicular lines, the product of their slopes is equal to -1.

Let us find the slopes of each lines.

Option A:

$y=3x-10$

On comparing with the slope-intercept form, we get slope as $m_{A}=3$ .

Now, $m\times m_{A}=-\frac{1}{3}\times 3=-1$ . So, option A is perpendicular to the given line.

Option B:

For lines of the form $x=a$ , where, a is a constant, the slope is undefined. So, option B is incorrect.

Option C:

On comparing with the slope-point form, we get slope as $m_{C}=3$ .

Now, $m\times m_{C}=-\frac{1}{3}\times 3=-1$ . So, option C is perpendicular to the given line.

Option D:

$3x+9y=8\\9y=-3x+8\\y=-\frac{3}{9}x+\frac{8}{9}\\y=-\frac{1}{3}x+\frac{8}{9}$

On comparing with the slope-intercept form, we get slope as $m_{D}=-\frac{1}{3}$ .

Now, $m\times m_{D}=-\frac{1}{3}\times -\frac{1}{3}=\frac{1}{9}$ . So, option D is not perpendicular to the given line.

8 0

3 years ago