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oksano4ka [1.4K]
3 years ago
9

The histogram below shows the distribution of the assets (in millions of dollars) of 71 companies. Does the distribution appear

to be normal? Why or why not?
No, the assets do not appear to follow a normal distribution, the values are evenly concentrated.
Yes, the assets appear to follow a normal distribution, the values are evenly distributed. No, the assets do not appear to follow a normal distribution, the values are concentrated in the center and taper off towards the ends.
Yes, the assets appear to follow a normal distribution, the values are concentrated in the center and taper off towards the ends.

Mathematics
1 answer:
solniwko [45]3 years ago
7 0

Answer:

Yes, the assets appear to follow a normal distribution, the values are concentrated in the center and taper off towards the ends

Step-by-step explanation:

The distribution shown above is normal as it exhibits symmetry. This means thatvtge values are concentrated in the middle with the peak so situated in the middle of the distribution which is exactly what is displayed above. As we move towards either side of the center, the values begin to decrease and we have the tail at either side of the midpoint and not on one side of the distribution.

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A woman in a highland village in the Andes knits sweaters and sells them for export. She also takes care of her family and helps
Mnenie [13.5K]

Answer:

Expected number of sweaters per month can be given as follows:

E(X) = Σ x P(X = x)

Now,

E(X) = [2 * 0.1 + 3* 0.1+ 4* 0.2 + 5* 0.3 + 6* 0.2 + 7 * 0.1]

E(X) = 4.7.

Var(X) = E(X^2) – [E(X)]^2

     We have E(X) = 4.7. Thus, [E(X)]2= 4.7*4.7 = 22.09.

Now E(X^2) = [2*2 * 0.1 + 3*3* 0.1+ 4*4* 0.2 + 5*5* 0.3 + 6*6* 0.2 + 7*7*0.1]

    E(X^2) = 24.1

Thus by formula, Var(X) = E(X2) – [E(X)]2

Var(X) = 24.1-22.09

Var(X) = 2.01

Given that exporter pays the $12 for each sweater. The woman pays $2 per sweater. The cost of shipment is $3 irrespective of the number of sweaters. Now, let m is the number of sweaters she made. Thus, the total cost she would have to pay would be

Total cost by woman = 2m+3

The total cost paid by the exporter would be = 12m.

Now the profit of woman would be given by,

                  = The total cost exporter pay – cost paid by the woman

                 = 12m – (2m +3)

                 = 12m – 2m -3

                 = 10m – 3.

Now expected profit made by the woman is given in the following table below:

E(Profit) = Σ profit* P(X = x)

In a similar way, as we have done in part (a).

E(Profit) = [17 * 0.1 + 27* 0.1+ 37* 0.2 + 47* 0.3 + 57* 0.2 + 67 * 0.1]

E(Profit) = 44.

Now, we calculate the variance:

Var(profit) = E(profit^2) – [E(profit)]^2

Var(profit) =

E(profit^2) = [17*17 * 0.1 + 27*27* 0.1+ 37*37* 0.2 + 47*47* 0.3 + 57*57* 0.2 + 67*67*0.1]

    E(profit^2) = 2137.

[E(profit)]^2 = 44*44 = 1936.

Thus, the variance can be given as =

Var(profit)= 2137 – 1936

Var(profit) = 201.

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Answer:

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Answer:

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Step-by-step explanation:

the number is 38,266,830

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Answer:

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Step-by-step explanation:

-2xy

Let x = -1 and y =6

-2 ( -1) (6)

Multiply

2 (6)

12

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