The answer is 2/16 if you do the math with the numerators only.
Check the attachment below. Answer: 5/2
Answer:
{
x
∣
x
>
1
} or x
∈
(
1
,
∞
)
Step-by-step explanation:
2
x
+
3
>
7
⇒
2
x
>
4
(subtract 3 from both sides)
2
x
+
3
>
7
⇒
x
>
2
(divide both sides by 2)
2
x
+
9
>
11
⇒ 2
x
>
2
(subtract 9 from both sides)
2
x
+
9
>
11
⇒
x
>
1
(divide both sides by 2)
if an x
-value is greater than 2, it will automatically be greater than 1. Thus, the solution set for 2
x+
3
>
7 is a subset of the one for 2
x
+
9
>11
.That means, all we need to do here is list the solution set for 2
x
+
9
>
11
, and we're done.
The solution set we need is simply "all x such that x is greater than 1", or {
x
∣
x
>
1
}
or
x
∈
(
1
,
∞
)
2. Definition of perpendicular lines
3. Given
4. SD and DS are congruent
5. HL theorem
Answer:
itsn't it 64 it says it there
Step-by-step explanation: