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Nookie1986 [14]
3 years ago
11

Plssss help what is x

Mathematics
1 answer:
makvit [3.9K]3 years ago
8 0

Answer:

x = 4

Step-by-step explanation:

If you do not want to read the explanation go the the next part in bold

Ok so the shorter leg of the triangle is a radius of the circle. ( This is indicated by the point in the middle of the circle.) for the hypotenuse we are given one part of the length (2) The other part also happens to be a radius ( remember that a radius is a line that starts from the center of the triangle to any point of the circumference. ) Also remember that the radius is equal to 3. That being said the hypotenuse = 2+3 which equals 5.  

This triangle then happens to be a right triangle. ( A triangle formed by a tangent line and a radius is a right triangle.) This means that we can use the Pythagorean theorem to solve for x.

Below here is where the work is shown

a² + b² = c². where a and b = legs and c = hypotenuse. We are given the hypotenuse (5) and a leg (3) So we plug in what we are given and solve for the missing information. 5² = 3² + b²  

5² = 25

3² = 9

we would then have 25 = 9 + b²

Next we subtract 9 from each side

25 - 9 = 16

9 - 9 cancels out

Now we have 16 = b²

finally we want to get rid of the ²

To do so we take the square root of each side

\sqrt{16}=4\\\sqrt{b^2}=b\\b = 4

we're left with b = 4 which means that x = 4

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You must design a closed rectangular box of width w, length l and height h, whose volume is 504 cm3. The sides of the box cost 3
Charra [1.4K]

Answer:

Dimensions will be

Length = 7.23 cm

Width = 7.23 cm

Height = 9.64 cm

Step-by-step explanation:

A closed box has length = l cm

width of the box = w cm

height of the box = h cm

Volume of the rectangular box = lwh

504 = lwh

h=\frac{504}{lw}

Sides which involve length and width and height, cost = 3 cents per cm²

Top and bottom of the box costs = 4 cents per cm²

Cost of the sides C_{s}= 3[2(l + w)h] = 6(l + w)h

C_{s}= 3[2(l + w)h]

C_{s}=6(l+w)(\frac{504}{lw} )

Cost of the top and the bottom C_{(t,p)}= 4(2lw) = 8lw

Total cost of the box C = 3024\frac{(l+w)}{lw} + 8lw

                                      = 3024[\frac{1}{l}+\frac{1}{w}] + 8lw

To minimize the cost of the sides

\frac{dC}{dl}=3024(-l^{-2}+0)+8w=0

\frac{3024}{l^{2}}=8w

\frac{378}{l^{2}}=w ---------(1)

\frac{dC}{dw}=3024(-w^{-2})+8l=0

\frac{3024}{w^{2}}=8l

\frac{378}{w^{2}}=l

w^{2}=\frac{378}{l}-------(2)

Now place the value of w from equation (1) to equation (2)

(\frac{378}{l^{2}})^{2}=\frac{378}{l}

\frac{(378)^{2} }{l^{4}}=\frac{378}{l}

l³ = 378

l = ∛378 = 7.23 cm

From equation (2)

w^{2}=\frac{378}{7.23}

w^{2}=52.28

w = 7.23 cm

As lwh = 504 cm³

(7.23)²h = 504

h=\frac{504}{(7.23)^{2}}

h = 9.64 cm                        

6 0
3 years ago
Angle A and angle B are complementary angles. If m<A = x, which expression represents the number of degrees in angle B?
Usimov [2.4K]
Complimentary just means that they add to be 90, so you take 90 degrees and subtract the angle you already have in order to get the complementary angle
8 0
3 years ago
on Saturday Leo and his brother drove into town to visit their mom Leo is trying to remember how much he spent on gas and tolls
Gwar [14]

Let t be the number of tolls they crossed.

Amount they spent at each toll = $1.75.

Amount they spent at gas station = $28.

Let C be the total amount they spent on gas and tolls.

If they crossed 1 toll, then

C = 28 + 1.75(1).

If they crossed 3 tolls, then,

C = 28 + 1.75(3)

If they crossed t tolls, then,

C = 28 + 1.75t

Here, the terms are 28 and 1.75t and the factors are 1.75 and t.

8 0
3 years ago
14. Alex earns $7.50 per hour by working after school. He should have at least $60 for buying a video
slavikrds [6]

Answer:

7.50x = 60

x = 8

Step-by-step explanation:

He would have to work 8 hours because 8*7.50=60

Hope I helped :)

8 0
3 years ago
Read 2 more answers
2/x2-9 - 3x/ x2-5x+6 please show work
Luda [366]

Answer: -3x^3 - 7x^2 - x + 39

Step-by-step explanation:

2/(x^2 -9) - 3x/(x^2-5x+6)

get those denominators factored out

2/(x-3)(x+3) - 3x/(x-3)(x-2)

Multiply both by both denominators

2(x-3)(x-2) - 3x(x-3)(x+3)

Multiply it out

(2x^2 - 10x + 12) - (3x^3 + 9x^2 -9x - 27)

Simplify and it becomes

-3x^3 -7x^2 -x + 39

5 0
3 years ago
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