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2 years ago

9

Make m the subject of the formula

title="s = \frac{hm}{4} " alt="s = \frac{hm}{4} " align="absmiddle" class="latex-formula">

1 answer:

juin [17]2 years ago

4 0

S = hm / 4

4s = hm

4s / h = m

So, m = 4s/h

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(a) An angle measures 43 . What is the measure of its complement? (b) An angle measures 81 . What is the measure of its suppleme

vampirchik [111]

To solve the problem shown above, you must follow the proccedure shown below:

1. By definition, Completary angles are those angles whose sum is 90 degrees and Suplementary angles are those angles whose sum is 180 degrees.

2. Keeping the information above on mind, you have:
<span>
(a) An angle measures 43 . What is the measure of its complement?

=90°-43°
=47°

(b) An angle measures 81 . What is the measure of its supplement?
</span>
=180°-81°
=99°

The answers are:

a) 47°
b) 99°

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2 years ago

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allochka39001 [22]

-18/35

is the answer hope I am helpful

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2 years ago

Leno4ka [110]

Answer:

$\frac{s^2-25}{(s^2+25)^2}$

Step-by-step explanation:

Let's use the definition of the Laplace transform and the identity given: $\mathcal{L}[t \cos 5t]=(-1)F'(s)$ with $F(s)=\mathcal{L}[\cos 5t]$ .

Now, $F(s)=\int_0 ^{+ \infty}e^{-st}\cos(5t) dt$ . Using integration by parts with u=e^(-st) and dv=cos(5t), we obtain that $F(s)=\frac{1}{5}\sin(5t)e^{-st} |_{0}^{+\infty}+\frac{s}{5}\int_0 ^{+ \infty}e^{-st}\sin(5t) dt=\int_0 ^{+ \infty}e^{-st}\sin(5t) dt$ .

Using integration by parts again with u=e^(-st) and dv=sin(5t), we obtain that

$F(s)=\frac{s}{5}(\frac{-1}{5}\cos(5t)e^{-st} |_{0}^{+\infty}-\frac{s}{5}\int_0 ^{+ \infty}e^{-st}\sin(5t) dt)=\frac{s}{5}(\frac{1}{5}-\frac{s}{5}\int_0^{+ \infty}e^{-st}\sin(5t) dt)=\frac{s}{5}-\frac{s^2}{25}F(s)$ .

Solving for F(s) on the last equation, $F(s)=\frac{s}{s^2+25}$ , then the Laplace transform we were searching is $-F'(s)=\frac{s^2-25}{(s^2+25)^2}$

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2 years ago

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katovenus [111]

Answer:

Step-by-step explanation:

P-6 is an expression, your question is incomplete.

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Family bought 12 oranges from the market. However, one-fourth of these oranges were rotten. How many oranges were not rotten?

sashaice [31]

Answer:

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2 years ago