Answer:
Advance ticket costs $25
Same-day ticket costs $20
Step-by-step explanation:
Let x = the price of one the advance ticket.
Let y = the price of one same-day ticket.
The combined cost of one advance ticket and one same-day ticket is $ 45. This means
x + y = 45 - - - - - - 1
For one performance, 30 advance tickets and 20 same-day tickets were sold. The total amount paid for the tickets was $ 1150. This means
30x + 20y = 1150 - - - - - - - - -2
From equation 1, x = 45- y
Put x = 45- y in equation 2
30( 45-y) + 20y = 1150
1350 - 30y + 20y = 1150
-10y = 1150-1350
-10y = -200
y = 200/10 = $20
x = 45-y
x =45-20= $25
Advance ticket costs $25
Same-day ticket costs $20
Answer:
$637.5
Step-by-step explanation:
Given data
Cost of merchandise= $750
Discount= 15%
Let us find the amount of the discount
=15/100*750
=0.15*750
=$112.5
Hence the amount paid will be
=750-112.5
=$637.5
Remember you can do anything to do anything to an equation as long as you do it to both sides
n-8<10
add 8 to both sides
n-8+8<10+8
n+0<18
n<18
Answer:
1656.4128 BC 3.14*2 and * 263.76
Step-by-step explanation:
