3 years ago

Geometry help needed! Thanks.

Mathematics

1 answer:

VMariaS [17]3 years ago

4 0

EN = NE

Answer

D. last one

You might be interested in

Proove that <br>1/1-sin theta + 1/1+cos theta = 2×sec square theta

Rina8888 [55]

Step-by-step explanation:

We need to prove that,

$\dfrac{1}{1-\sin\theta}+\dfrac{1}{1+\sin\theta}=2\times \sec^2\theta$

Taking LHS,

$\dfrac{1}{1-\sin\theta}+\dfrac{1}{1+\sin\theta}\\\\=\dfrac{(1+\sin\theta)+(1-\sin\theta)}{(1-\sin\theta)(1+\sin\theta)}\\\\=\dfrac{2}{1-\sin^2\theta}\\\\\text{As}\ 1-\sin^2\theta=\cos^2\theta\\\\=\dfrac{2}{\cos^2\theta}\\\\\text{As}\ \dfrac{1}{\cos^2\theta}=\sec^2\theta\\\\=2\sec^2\theta\\\\=RHS$

Hence, LHS = RHS.

4 0

3 years ago

There were 532 people at the Nutcracker. If admission was $24 for adults and $16 for children and $10,272 was collected, how man

anzhelika [568]

X = # adults

y = # children

system

24x+16y=$10272
x + y =532

4 0

3 years ago

Find the circumference and area <br> r = 5 m

stira [4]

Step-by-step explanation:

Let's get our relevant base equations listed out:

d = 2r

area = pi*r²

c = πd

Thus, d=2*5m = 10m, c=π*10m=10π m, and area = 25m²*π

Feel free to ask further questions!

4 0

3 years ago

A relay race covers 1 1/2 kilometers, and each runner on a team will rub 1/4 of a kilometers. How many runners are needed for a

VikaD [51]

We need to find how many 1/4 groups are in 1 1/2.
I work better with decimals, so I'll just convert them into decimals. We're dividing to see how many people we need.
1.5÷0.25
6
So, you'll need 6 runners for the relay race.

8 0

3 years ago

Read 2 more answers

If 20% of the students in your class like McDonald's, how many students are in your class if 4 students like McDonald's?

elena55 [62]

Answer: it is 20 students

5 0

3 years ago

Read 2 more answers