Answer:
18 units
Step-by-step explanation:
So let's list out the sides.
for the first square let's just call them x
for the second square then they would be x+5 and x-3
So let's write out their areas we will cal the area of the first one z
x*x = z
(x+5)*(x-3) = z+21
since z = x^2 we can set up the second equation as a quadratic.
(x+5)*(x-3) = x^2 + 21
x^2 - 3x + 5x - 15 = x^2 + 21
But look, the x^2s cancel out
2x - 15 = 21
2x = 36
x = 18
Test it out and see if it fits the description, And if you don't understand anything just let me know so I can explain more.
Answer:
3x^2−13x+4
Step-by-step explanation:
(x−4)(3x−1)
=(x+−4)(3x+−1)
=(x)(3x)+(x)(−1)+(−4)(3x)+(−4)(−1)
=3x^2−x−12x+4
=3x^2−13x+4
