So, (weekly) she receives 1036.00.
The question is asking to find out the (annual) salary which is a year.
There are about 52 weeks in a year.
To find the amount being payed annually we multiply 1036 by 52
=53,872.
Step-by-step explanation:

is a root of the quadratic

This quadratic isn't factorable so use the quadratic formula

The plus and minus sign after b means we going to have two roots.
The roots are

and

We subsitue those values for Beta.
27a.

27b.
25
Answer:

Step-by-step explanation:
We have the compound inequality:

Let's solve each of them individually first:
We have:

Divide both sides by 2:

Add 1 to both sides:

We have:

Subtract from both sides:

Divide both sides by -4:

Hence, our solution set is:

Answer:
A
Step-by-step explanation:
6x-20= 118
6x= 118 + 20
6x = 138
x = 138/6
x= 23