The vertical asympototes of f(x) are at x = -6 and x = 6
Step-by-step explanation:
To find the vertical asymptote(s) of a rational function,
- Equate the denominator by 0
- Solve it for x
- If x = a, then the vertical asymptote is at x = a
∵ ![f(x)=\frac{4x^{2}+3x+6}{x^{2}-36}](https://tex.z-dn.net/?f=f%28x%29%3D%5Cfrac%7B4x%5E%7B2%7D%2B3x%2B6%7D%7Bx%5E%7B2%7D-36%7D)
- Equate the denominator x² - 36 by 0
∵ x² - 36 = 0
- Add 36 to both sides
∴ x² = 36
- Take √ for both sides
∴ x = ± 6
∴ There are vertical asymptotes at x = -6 and x = 6
The vertical asympototes of f(x) are at x = -6 and x = 6
Learn more:
You can learn more about the asymptotes in brainly.com/question/6459599
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Median, upper quartile, and maximum are all incorrect