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3 years ago

Joanna set a goal to drink more water daily. The number of ounces of water she drank each of the last seven days is shown below.

Mathematics

1 answer:

DaniilM [7]3 years ago

6 0

(a) Data with the eight day's measurement.

Raw data: [60,58,64,64,68,50,57,82],

Sorted data: [50,57,58,60,64,64,68,82]

Sample size = 8 (even)

mean = 62.875

median = (60+64)/2 = 62

1st quartile = (57+58)/2 = 57.5

3rd quartile = (64+68)/2 = 66

IQR = 66 - 57.5 = 8.5

(b) Data without the eight day's measurement.

Raw data: [60,58,64,64,68,50,57]

Sorted data: [50,57,58,60,64,64,68]

Sample size = 7 (odd)

mean = 60.143

median = 60

1st quartile = 57

3rd quartile = 64

IQR = 64 -57 = 7

Answers:

1. The average is the same with or without the 8th day's data. FALSE

2. The median is the same with or without the 8th day's data. FALSE

3. The IQR decreases when the 8th day is included. FALSE

4. The IQR increases when the 8th day is included. TRUE

5. The median is higher when the 8th day is included. TRUE

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2x-7/3-5x+4/5=-x-4/30

Strike441 [17]

Answer:

Exact form: -7/10

Decimal form: -0.7

Step-by-step explanation:

Isolate the variable by dividing each side by by factors that don't contain the variable.

5 0

2 years ago

Find the distance travelled by Rubina if she takes 4 rounds of rectangular park whose length and breadth is 45m and 30m

ANTONII [103]

Length (l) = 45 m
Breadth (b) = 30 m
We know, perimeter of a rectangle = 2(length + breadth)
Therefore, perimeter of the rectangle
= 2(I + b)
= 2(45 + 30) m
= 2 × 75 m
= 150 m
So, the distance travelled by Rubina
= 4 × 150 m
= 600 m

Answer:

The distance travelled by Rubina is 600 m.

Hope you could get an idea from here.

Doubt clarification - use comment section.

5 0

2 years ago

ABC Auto Insurance classifies drivers as good, medium, or poor risks. Drivers who apply to them for insurance fall into these th

Misha Larkins [42]

Answer:

a. $P(E_1/A)=0.0789$

b. $P(E_2/A)=0.395$ \

c. $P(E_3/A)=0.526$

Step-by-step explanation:

Let $E_1,E_2,E_3$ are the events that denotes the good drive, medium drive and poor risk driver.

$P(E_1)=0.30,P(E_2)=0.50,P(E_3)=0.20$

Let A be the event that denotes an accident.

$P(A/E_1)=0.01$

$P(A/E_2=0.03$

$P(A/E_3)=0.10$

The company sells Mr. Brophyan insurance policy and he has an accident.

a.We have to find the probability Mr.Brophy is a good driver

Bayes theorem, $P(E_i/A)=\frac{P(A/E_i)\cdot P(E_1)}{\sum_{i=1}^{i=n}P(A/E_i)\cdot P(E_i)}$

We have to find $P(E_1/A)$

Using the Bayes theorem

$P(E_1/A)=\frac{P(A/E_1)\cdot P(E_1)}{P(E_1)\cdot P(A/E_1)+P(E_2)P(A/E_2)+P(E_3)P(A/E_3)}$

Substitute the values then we get

$P(E_1/A)=\frac{0.30\times 0.01}{0.01\times 0.30+0.50\times 0.03+0.20\times 0.10}$

$P(E_1/A)=0.0789$

b.We have to find the probability Mr.Brophy is a medium driver

$P(E_2/A)=\frac{0.03\times 0.50}{0.038}=0.395$

c.We have to find the probability Mr.Brophy is a poor driver

$P(E_3/A)=\frac{0.20\times 0.10}{0.038}=0.526$

7 0

3 years ago

Using this formula, what is the acceleration of an object with F = 7.92 newtons and m = 3.6 kilograms? Express your answer to th

g100num [7]

We have to use the following formula which is

$F = m * a$

Given values of F and m are 7.92 Newtons and 3.6 kilograms .

Substituting these values in the formula, we will get

$7.92 = 3.6 a$

To solve for a, we have to divide both sides by 3.6 that is

$a = \frac{7.92}{3.6}=2.2$

And that's the required answer .

8 0

3 years ago

Read 2 more answers

What is the solution to the equation 3(y-2)=2y-8 A.-2/5 B.-14 C. -2 D. -2 4/5 I NEED-HELP PLeAse

AlladinOne [14]

3(y - 2) = 2y - 8

3y - 6 = 2y - 8

3y - 2y = -8 + 6

y = -2

Answer: C

4 0

2 years ago