So 3/8 + 4/8 + 5/8 + 7/8 + 1 2/8 =
3 5/8
Answer:
Surface area of square pyramid is computed as follows:
A = a² + a*√(a² + 4h²)
where <em>a</em> is the base length and <em>h</em> is the height.
If a model of the square pyramid is scaled down by a factor of x, then the surface area will be:
A' = (a/x)² + (a/x)*√[(a/x)² + 4(h/x)²]
A' = a²/x² + a/x * √[a²/x² + 4h²/x²]
A' = a²/x² + a/x * √[(a² + 4h²)/x²]
A' = a²/x² + a/x * √(a² + 4h²)/√x²
A' = a²/x² + a/x² * √(a² + 4h²)
A' = 1/x² * [a² + a*√(a² + 4h²)]
A' = 1/x² * A
That is, the surface area will be 1/x² times the original surface area. If h = 25 ft and a = 15 ft:
A = 15² + 15*√(15² + 4(25)²) = 1008.02 ft²
The factor is not mentioned in the question, nevertheless, the area will be 1008.02/factor² ft²
Answer:
the mean is 24
standard.8x^3+2x^2+4x=64
Step-by-step explanation:
Answer:
Step-by-step explanation:
The equation representing the growth of the plant after x weeks is expressed as
y = 0.2x+2
Where
x represents the number of weeks.
y represents the height of the plant after x weeks in inches.
A.
The height of the plant after week 3 was about 2.6 inches. We can check by substituting x = 3 into the equation. It becomes
y = 0.2 × 3 + 2 = 2 + 0.6 = 2.6 inches. It is correct.
B is incorrect.
C.
The height of the plant after week 9 was about 3.8 inches. We can check by substituting x = 9 into the equation. It becomes
y = 0.2 × 9 + 2 = 2 + 1.8 = 3.8 inches. It is correct.
D is incorrect
Answer:
Step-by-step explanation:
just simplify the LHS first.
You can either multiply 1/5 by (x+3) and then solve
or
multiply both sides by 5 to get rid of 1/5 on LHS
I will multiply by 5
(x+3)= -10x-15 ( 5*1/5(x+3)= -5(2x+3)
now rearrange the equation
x+3=-10x-15
-10x-15-x-3=0
-11x-17=0
-11x=17
x= -17/11
