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Afina-wow [57]
3 years ago
7

Xian and his cousin Kai both collect stamps. Xian has 56 stamps, and Kai has 80 stamps. The boys recently joined different stamp

collecting clubs. Xians club will send him 12 new stamps per month. Kai’s club will send him 8 new stamps per month. After how many months will Xian and Kai have the same number of stamps? How many stamps will they each have?

Mathematics
1 answer:
kondaur [170]3 years ago
4 0

Answer:

all work is pictured/shown

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What is the balue of x in the proportion 2 1/4 / x= 1 1/2/3/35?
never [62]

Answer:

5 2/5

Step-by-step explanation:

(2 1/4) / x = (1 1/2) / (3 3/5)

so

x = (2 1/4) * (3 3/5) / (1 1/2)

7 0
3 years ago
A package contains 12 resistors, 3 of which are defective. If 4 are selected, find the probability of getting
s344n2d4d5 [400]

Answer:

Incomplete question, but I gave a primer on the hypergeometric distribution, which is used to solve this question, so just the formula has to be applied to find the desired probabilities.

Step-by-step explanation:

The resistors are chosen without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

In this question:

12 resistors, which means that N = 12

3 defective, which means that k = 3

4 are selected, which means that n = 4

To find an specific probability, that is, of x defectives:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

P(X = x) = h(x,12,4,3) = \frac{C_{3,x}*C_{9,4-x}}{C_{12,4}}

7 0
3 years ago
100 POINTS GEOMETRY QUESTION PLEASE ANSWER !!!!!!
Ilia_Sergeevich [38]

Answer:

Step-by-step explanation:

ABC have sides: 5, 7 and 10

5^2 + 7^2 = 25+47 = 72 < 10^2

so triangle ABC is obtuse

JKL has sides: 12, 35 and 37

12^2 + 35^2 = 144 + 1225 = 1369 = 37^2

so triangle JKL is right-angled

PQR has sides 12, 10 and 16

12^2 + 10^2 = 144 + 100 = 244 > 16^2

so triangle PQR is acute

5 0
3 years ago
Read 2 more answers
Write the ratio $12 dollers for 3 tickets as a unit rate​
guajiro [1.7K]

The unit rate would be the price for 1 ticket.

12 dollars / 3 tickets = $4 per ticket.

The ratio would be 4:1

8 0
3 years ago
(c) दिइएको त्रिभुजमा कुन-कुन अनुरुप छन् ?
Paha777 [63]
There needs to be a picture of the triangles
6 0
3 years ago
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