C is the answer hope this helps please give me brainliest
Answer:
Step-by-step explanation:
First, multiply the two denominators together to get the shared denominator, which will allow you to actually subtract the two numbers. 4 × 8 = 32, so the shared denominator will be 32.
Then, cross-multiply. 11 × 8 = 88, so 
becomes 
. 3 × 4 = 12, so 
becomes 
.
Now, you can subtract. 
Finally, simplify. 
. The final difference is .
Answer: Q=1/2p+15,= p=2q-30= Slope = 1.000/2.000 = 0.500
p-intercept = -30/1 = -30.00000
q-intercept = 30/2 = 15
Step-by-step explanation: Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :
p-(2*q-30)=0
Solve p-2q+30 = 0
we have an equation of a straight line. Such an equation is usually written y=mx+b ("y=mx+c" in the UK).
"y=mx+b" is the formula of a straight line drawn on Cartesian coordinate system in which "y" is the vertical axis and "x" the horizontal axis.
In this formula :
y tells us how far up the line goes
x tells us how far along
m is the Slope or Gradient i.e. how steep the line is
b is the Y-intercept i.e. where the line crosses the Y axis
The X and Y intercepts and the Slope are called the line properties. We shall now graph the line p-2q+30 = 0 and calculate its properties
Notice that when p = 0 the value of q is 15/1 so this line "cuts" the q axis at q=15.00000
q-intercept = 30/2 = 15
When q = 0 the value of p is -30/1 Our line therefore "cuts" the p axis at p=-30.00000
p-intercept = -30/1 = -30.00000
Slope is defined as the change in q divided by the change in p. We note that for p=0, the value of q is 15.000 and for p=2.000, the value of q is 16.000. So, for a change of 2.000 in p (The change in p is sometimes referred to as "RUN") we get a change of 16.000 - 15.000 = 1.000 in q. (The change in q is sometimes referred to as "RISE" and the Slope is m = RISE / RUN)
Slope = 1.000/2.000 = 0.500
Answer:
a. <u>x1 = No. of units to purchase from Iowa</u>
<u>x2 = No. of units to purchase from Illinois</u>
<u></u>
b. <u>Min 6x1 + 5.5x2</u>
<u></u>
c. <u>x1 + x2 ≥ 12000</u>
<u>x1 ≤ 8000</u>
<u>x2 ≥ 6000</u>
Step-by-step explanation:
a. We can consider the variables x1 and x2 as:
<u>x1 = No. of units to purchase from Iowa</u>
<u>x2 = No. of units to purchase from Illinois</u>
<u></u>
b. Price per unit of Iowa corn = $6
Price per unit of Illinois corn = $5.5
Objective function that would minimize the total cost can be written as:
<u>Min 6x1 + 5.5x2</u>
<u></u>
c. The manufacturer needs at least 12000 units of corn which means that the combined number of units from Iowa and Illinois must be greater than or equal to 12000. So, we can write:
x1 + x2 ≥ 12000
The Iowa cooperative can supply up to 8000 units which means that the value of x1 must not be greater than 8000. So, we can write:
x1 ≤ 8000
Similarly, the Illinois cooperative can supply at least 6000 units which means that the value of x2 must not be less than 6000. So, we can write:
x2 ≥ 6000.
The constraints for these conditions are:
<u>x1 + x2 ≥ 12000</u>
<u>x1 ≤ 8000</u>
<u>x2 ≥ 6000</u>
Xy = 6
x = 2
2y = 6
y = 6÷2
y = 3
x + y = (2) + (3) = 5
