Well the 2 in the tens place is ten times as many as the 2 in the hundreds place.Also the 5 in the thousand place is 10 times as many as the 5 in the ten thousand place
Answer:
x = 3
Step-by-step explanation:
using the mid segment formula since quadrilateral WZYP is similar to that of MZYT, this is expressed as;
29 = 1/2(23 +11x+2)
Cross multiply
2(29) = 23+11x+2
58 = 25 + 11x
11x = 58 - 25
11x = 33
Divide both sides by 11
11x/11 = 33/11
x = 3
Hence the value of x is 3
Answer: y=6
Step-by-step explanation:
The given number is y.
According to the question,
Step 1 . subtracts three from the number (y-3), then doubles it
i.e. Final number = 2(y-3)
Step 2 . subtracts three again i.e. (2(y-3)-3), and doubles the number again
i.e. Final result = 2(2(y-3)-3)
If the result is his original number y, then
2(2(y-3)-3) =y
⇒ 2(2y-6-3)=y [ using distributive property]
⇒ 2(2y-9)=y
⇒ 2(2y)-2(9)=y [ using distributive property]
⇒ 4y -18=y
⇒ 4y -y= 18
⇒ 3y= 18
⇒ y= 6 [Divide both sides by 3]
Hence, y=6
Using Gauss's method
Total number of terms = [15-(-129)]/4+1=36+1=37
Add
S=15+11+7+....-125-129
S=-129-125-...+7+11+15
--------------------------------
2S=-114-114-114...(37 times)
=>
sum=S=(1/2)*(-114)*37=-2109
Using AP, T(n)=15+11+7+....-129
T(n)=19-4n => T(1)=15, T(37)=-129
S(n)=(1/2)(37)(T(1)+T(37)=(1/2)37(15-129)=2109
